Fullstack Developer

Design and implement a data structure for Least Recently Used (LRU) cache to support the following operations:

1. get(key) - Return the value of the key if the key exists in the cache, otherwise return -1.

2. put(key, value), Insert the value in the cache if the key is not already present or update the value of the given key if the key is already present. When the cache reaches its capacity, it should invalidate the least recently used item before inserting the new item.

You will be given ‘Q’ queries. Each query will belong to one of these two types:

Type 0: for get(key) operation.
Type 1: for put(key, value) operation.

Note :

1. The cache is initialized with a capacity (the maximum number of unique keys it can hold at a time).

2. Access to an item or key is defined as a get or a put operation on the key. The least recently used key is the one with the oldest access time.

Mutex, Semaphore

Indexing, types of indexing, internal data structure of indexing, Normalization, Normalization vs De-Normalization, ACID property.
SQL queries on finding nth highest salary. Difference between stored procedures and functions.

You are given an array 'a' of size 'n'.

Print the Next Greater Element(NGE) for every element.

The Next Greater Element for an element 'x' is the first element on the right side of 'x' in the array, which is greater than 'x'.

If no greater elements exist to the right of 'x', consider the next greater element as -1.

For example:

Input: 'a' = [7, 12, 1, 20]

Output: NGE = [12, 20, 20, -1]

Explanation: For the given array,

- The next greater element for 7 is 12.

- The next greater element for 12 is 20. 

- The next greater element for 1 is 20. 

- There is no greater element for 20 on the right side. So we consider NGE as -1.

You have been given a non-empty grid ‘mat’ with 'n' rows and 'm' columns consisting of only 0s and 1s. All the rows are sorted in ascending order.

Your task is to find the index of the row with the maximum number of ones.

Note: If two rows have the same number of ones, consider the one with a smaller index. If there's no row with at least 1 zero, return -1.

Example:

Input: 'n' = 3, 'm' = 3, 'mat' = [[1, 1, 1], [0, 0, 1], [0, 0, 0]]

Output: 0

Explanation: The row with the maximum number of ones is 0 (0 - indexed).

Basic discussion over LLD of Jira software. Previous internship experience and other technical questions.