Technical Consultant

Given an array 'arr' with 'n' elements, the task is to rotate the array to the left by 'k' steps, where 'k' is non-negative.

Example:

'arr '= [1,2,3,4,5]
'k' = 1  rotated array = [2,3,4,5,1]
'k' = 2  rotated array = [3,4,5,1,2]
'k' = 3  rotated array = [4,5,1,2,3] and so on.

Given a linked list of 'N' nodes, where each node has an integer value that can be 0, 1, or 2. You need to sort the linked list in non-decreasing order and the return the head of the sorted list.

Example:

Given linked list is 1 -> 0 -> 2 -> 1 -> 2. 
The sorted list for the given linked list will be 0 -> 1 -> 1 -> 2 -> 2.

Given an array/list of integer numbers 'CHOCOLATES' of size 'N', where each value of the array/list represents the number of chocolates in the packet. There are ‘M’ number of students and the task is to distribute the chocolate to their students. Distribute chocolate in such a way that:

1. Each student gets at least one packet of chocolate.

2. The difference between the maximum number of chocolate in a packet and the minimum number of chocolate in a packet given to the students is minimum.

Example :

Given 'N' : 5 (number of packets) and 'M' : 3 (number of students)

And chocolates in each packet is : {8, 11, 7, 15, 2}

All possible way to distribute 5 packets of chocolates among 3 students are -

( 8,15, 7 ) difference of maximum-minimum is ‘15 - 7’ = ‘8’
( 8, 15, 2 ) difference of maximum-minimum is ‘15 - 2’ = ‘13’ 
( 8, 15, 11 ) difference of maximum-minimum is ‘15 - 8’ = ‘7’
( 8, 7, 2 ) difference of maximum-minimum is ‘8 - 2’ = ‘6’
( 8, 7, 11 ) difference of maximum-minimum is ‘11 - 7’ = ‘4’
( 8, 2, 11 ) difference of maximum-minimum is ‘11 - 2’ = ‘9’
( 15, 7, 2 ) difference of maximum-minimum is ‘15 - 2’ = 13’
( 15, 7, 11 ) difference of maximum-minimum is ‘15 - 7’ = ‘8’
( 15, 2, 11 ) difference of maximum-minimum is ‘15 - 2’ = ‘13’
( 7, 2, 11 ) difference of maximum-minimum is ‘11 - 2’ = ‘9’

Hence there are 10 possible ways to distribute ‘5’ packets of chocolate among the ‘3’ students and difference of combination (8, 7, 11) is ‘maximum - minimum’ = ‘11 - 7’ = ‘4’ is minimum in all of the above.

There are 100 doors in a row, all doors are initially closed. A person walks through all doors multiple times and toggle (if open then close, if close then open) them in the following way: 

In the first walk, the person toggles every door 

In the second walk, the person toggles every second door, i.e., 2^nd, 4^th, 6^th, 8^th, … 

In the third walk, the person toggles every third door, i.e. 3^rd, 6^th, 9^th, … 

Likewise,

In the 100^th walk, the person toggles the 100^th door. 

Which doors are open in the end?