Tip 1 : Be thorough with your projects
Tip 2 : Have a good understanding of the basics of CSS, React.js, and Node.js
Tip 1 : MERN Stack projects
Tip 2 : Past internships
3 DSA questions, 2 SQL questions
On the DoSelect platform, which was good
You don’t have to multiply the matrices, you only have to find the minimum number of multiplication operations.
ARR = {2, 4, 3, 2}
Here, we have three matrices with dimensions {2X4, 4X3, 3X2} which can be multiplied in the following ways:
a. If the order of multiplication is (2X4, 4X3)(3X2), then the total number of multiplication operations that need to be performed are: (2*4*3) + (2*3*2) = 36
b. If the order of multiplication is (2X4)(4X3, 3X2), then the total number of multiplication operations that need to be performed are (2*4*2) + (4*3*2) = 40
It was a straightforward application of the matrix multiplication approach of DP
1. Consider ‘0’ based indexing.
Started off with introductions and projects related questions.
Basic javascript and CSS property-related questions.
An easy DSA question
We cannot use the element at a given index twice.
Try to do this problem in O(N) time complexity.
Two pointer approach, set approach
Introduction and two easy to medium DSA questions
1 ‘X’: Enqueue element ‘X’ into the end of the nth queue. Returns true after the element is enqueued.
2: Dequeue the element at the front of the nth queue. Returns -1 if the queue is empty, otherwise, returns the dequeued element.
Enqueue means adding an element to the end of the queue, while Dequeue means removing the element from the front of the queue.
Symbol Value
I 1
V 5
X 10
L 50
C 100
D 500
M 1000
3 is written as III in Roman numeral, just three ones added together. 13 is written as XIII, which is simply X + III. The number 25 is written as XXV, which is XX + V
Two pointer approach
Here's your problem of the day
Solving this problem will increase your chance to get selected in this company
How do you write a single-line comment in C++?