Introduction
This blog will discuss how to write a program to check whether the number is even or odd.
We are given a number, and we need to state whether the number is even or odd.
Example 1:
Sample Input:
a=5
Sample Output:
Odd
Example 2:
Sample Input:
a=6
Sample Output:
EvenApproach
The approach to write a program to check whether the number is even or odd is given below. Check whether the number, when divided by 2, yields the remainder 0. If the remainder is 0, then it’s an even number else, it’s an odd number.
Time Complexity for writing a program to check whether the number is even or odd = O(1).
It takes constant time.
Till now, I assume you must have got the basic idea of what has been asked in the problem statement. So, I strongly recommend you first give it a try. even or odd
Pseudo Code
Algorithm
________________________________________________________________
procedure evenodd():
___________________________________________________________________
1. Declare n, rem
2. rem=n%2
3. if(rem==0): even
4. Else: odd
5. Display even or odd
end procedure
___________________________________________________________________
Implementation
- C
- C++
- Java
- Python
- JS
- C#
C
#include <stdio.h>
int main() {
int n, rem;
printf("Enter the number : ");
scanf("%d", &n);
// checking for the remainder
rem = n % 2;
if (rem == 0)
printf("even\n");
else
printf("odd\n");
return 0;
}
You can also try this code with Online C Compiler
C++
#include<iostream>
using namespace std;
int main()
{
int n, rem;
cout << "Enter the number : ";
cin >> n;
//checking for the remainder
rem = n % 2;
if (rem == 0)
cout << "even" << endl;
else
cout << "odd" << endl;
return 0;
}
You can also try this code with Online C++ Compiler
Java
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the number : ");
int n = scanner.nextInt();
// checking for the remainder
int rem = n % 2;
if (rem == 0)
System.out.println("even");
else
System.out.println("odd");
scanner.close();
}
}
You can also try this code with Online Java Compiler
Python
n = int(input("Enter the number : "))
# checking for the remainder
rem = n % 2
if rem == 0:
print("even")
else:
print("odd")
You can also try this code with Online Python Compiler
JS
let readline = require('readline');
let rl = readline.createInterface({
input: process.stdin,
output: process.stdout
});
rl.question("Enter the number : ", function(n) {
// checking for the remainder
let rem = n % 2;
if (rem === 0)
console.log("even");
else
console.log("odd");
rl.close();
});
You can also try this code with Online Javascript Compiler
C#
using System;
class Program {
static void Main() {
Console.Write("Enter the number : ");
int n = int.Parse(Console.ReadLine());
// checking for the remainder
int rem = n % 2;
if (rem == 0)
Console.WriteLine("even");
else
Console.WriteLine("odd");
}
}
Output:
Sample Input:
Enter the number : 5
Sample Output:
odd
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