1.
Introduction
2.
Problem Statement
3.
Solution
4.
Solid Rectangular Asterisk Pattern
4.1.
Programming language: C
4.2.
Programming language: C++
4.3.
Programming language: Java
4.4.
Programming language: Python
5.
Hollow Rectangular Asterisk Pattern
5.1.
Programming language: C
5.2.
Programming language: C++
5.3.
Programming language: Java
5.4.
Programming language: Python
6.
6.1.
What is the Average Time Complexity of printing solid rectangles using an asterisk?
6.2.
What is the Average Time Complexity of printing Hollow rectangles using an asterisk?
7.
Conclusion
Last Updated: Mar 27, 2024
Easy

# Rectangles using Asterisk

Nagendra
1 upvote
Master Python: Predicting weather forecasts
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Ashwin Goyal
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## Introduction

The best way to learn how looping structures in general-purpose programming languages function is to use pattern programs. It assists newcomers in visualizing how each loop iteration works. Pattern programs are simply patterns made up of integers, alphabets, or symbols in a specific order. These kinds of pattern programs are simple to solve when employing the for loop condition. These are often asked questions in campus placements and career interviews.

## Problem Statement

Write a program to create hollow rectangular asterisk patterns. For example for a rectangle of length = 4 units and breadth = 2 units the output should be:

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## Solution

There can be two or more loops in each pattern program. The number of loops required is determined by the pattern's complexity. The first loop affects the row, whereas the second affects the column.

## Solid Rectangular Asterisk Pattern

The following code illustrates printing a Solid rectangular Asterisk Pattern:

### Programming language: C

The following code illustrates printing solid rectangle using asterisk in C :

#include<stdio.h>
int main()
{
int length=4;
int width = 3;
for (int a = 0; a < length; a++) //This loop is for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
printf("*"); //printing asterisk
}
printf("\n"); //ending line
}
return 0;
}

Output :

***
***
***
***

### Programming language: C++

The following code illustrates printing a solid rectangle using an asterisk in C++ :

#include <iostream>
using namespace std;
int main()
{
int length=4;
int width = 3;
for (int a = 0; a < length; a++) //loop for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
cout<<"*"; //printing asterisk
}
cout<<"\n"; //ending line
}
return 0;
}

Output :

***
***
***
***

### Programming language: Java

The following code illustrates printing a solid rectangle using an asterisk in Java :

public class Ninja {
public static void main(String[] args) {
int length=4;
int width = 3;
for (int a = 0; a < length; a++) //loop for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
System.out.print("*"); //printing asterisk
}
System.out.println(); //ending line
}

}
}

Output :

***
***
***
***

### Programming language: Python

The following code illustrates printing a solid rectangle using an asterisk in Python :

length=4;
width = 3;
for i in range(length): #loop for number of rows
for j in range(width):#loop for number of columns
print("*",end=''); #printing asterisk
print(); #ending line

Output :

***
***
***
***

## Hollow Rectangular Asterisk Pattern

The following code illustrates printing a Hollow Rectangular Asterisk Pattern:

### Programming language: C

The following code illustrates printing a hollow rectangle using an asterisk in C :

#include <stdio.h>
int main() {
int length=5,width=7;
for (int a = 0; a < length; a++) //loop for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
if (a==0 || a==length-1 || b==0 || b==width-1)
printf("*"); //printing asterisk
else
printf(" "); //printing spaces for hollow area
}
printf("\n"); //ending line
}
return 0;
}

Output :

### Programming language: C++

The following code illustrates printing a hollow rectangle using an asterisk in C++ :

#include <iostream>
int main() {
int length=5,width=7;
for (int a = 0; a < length; a++) //loop for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
if (a==0 || a==length-1 || b==0 || b==width-1)
cout<<"*"; //printing asterisk
else
cout<<" "; //printing spaces for hollow area
}
cout<<endl; //ending line
}
return 0;
}

Output :

### Programming language: Java

The following code illustrates printing a hollow rectangle using an asterisk in Java :

public class Ninja {
public static void main(String[] args) {
int length=5;
int width = 7;
for (int a = 0; a < length; a++) //loop for number of rows
{
for (int b = 0; b < width; b++) //loop for number of columns
{
if (a==0 || a==length-1 || b==0 || b==width-1)
System.out.print("*"); //printing asterisk
else
System.out.print(" "); //printing spaces for hollow area
}
System.out.println(); //ending line
}
}
}

Output :

### Programming language: Python

The following code illustrates printing hollow rectangle using asterisk in Python :

length=5;
width = 7;
for i in range(length): #loop for number of rows
for j in range(width):#loop for number of columns
if (i==0 or i==length-1 or j==0 or j==width-1):
print("*", end=''); #printing asterisk
else :
print(" ",end=''); #printing spaces for hollow area
print(); #ending line

Output :

You can practice by yourself with the help of online python compiler for better understanding.

### What is the Average Time Complexity of printing solid rectangles using an asterisk?

The Time Complexity of printing solid rectangles using an asterisk is O(n2).

### What is the Average Time Complexity of printing Hollow rectangles using an asterisk?

The Time Complexity of printing hollow rectangles using an asterisk is O(n2).

## Conclusion

In this article, we have extensively discussed printing rectangles using asterisk and their implementation in different programming languages. The article explains the different approaches used to print rectangles using asterisk viz. printing solid rectangular asterisk and printing hollow rectangular asterisk. There are many more approaches, but these are the most efficient in time and space.