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Problem of the day

You have been given the preorder and inorder traversal of a binary tree. Your task is to construct a binary tree using the given inorder and preorder traversals.

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You may assume that duplicates do not exist in the given traversals.
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For the preorder sequence = [1, 2, 4, 7, 3] and the inorder sequence = [4, 2, 7, 1, 3], we get the following binary tree.
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Detailed explanation

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The first line contains an integer ‘N’ denoting the number of nodes in the binary tree.
The second line case contains ‘N’ integers denoting the preorder traversal of the binary tree.
The third line contains ‘N’ integers denoting the inorder traversal of the binary tree.
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Print the level order traversal of the constructed binary tree separated by a single-space.
For example, the output for the tree depicted in the below image would be :
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Level Order Traversal:
1
2 3
4 5 6
7
Explanation :
Level 1 :
The root node of the tree is 1
Level 2 :
Left child of 1 = 2
Right child of 1 = 3
Level 3 :
Left child of 2 = 4
Right child of 2 = null
Left child of 3 = 5
Right child of 3 = 6
Level 4 :
Left child of 4 = null
Right child of 4 = 7
Left child of 5 = null
Right child of 5 = null
Left child of 6 = null
Right child of 6 = null
Level 5 :
Left child of 7 = null
Right child of 7 = null
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Here, if the node is null, print nothing. The above format was just to provide clarity on how the output is formed for a given tree.
The sequence will be put together in a single line separated by a single space. Hence, for the above-depicted tree, the output will be:
1 2 3 4 5 6 7
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You do not need to print anything; it has already been taken care of. You just need to return the root node of the constructed binary tree.
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5
1 2 4 7 3
4 2 7 1 3
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1 2 3 4 7
1 2 3
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The tree after the construction is shown below.
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2
1 2
2 1
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1 2
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1 <= N <= 3000
1 <= data <= 10^4
Where ‘N’ is the total number of nodes in the binary tree, and “data” is the value of the binary tree node.
Time Limit: 1sec
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Can you solve this in O(N) time complexity?
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