Problem of the day
Given a singly linked list, you have to detect the loop and remove the loop from the linked list, if present. You have to make changes in the given linked list itself and return the updated linked list.
Expected Complexity: Try doing it in O(n) time complexity and O(1) space complexity. Here, n is the number of nodes in the linked list.
Input format:
The first line of input contains two values: the number of nodes in the linked list and the value of the kth node from which the last node connects to form the loop while the second line of input contains the given linked list.
The value of k should be greater than or equal to 0 and less than equal to n. For, k equal to 0, there is no loop present in the linked list and for k equal to n, the last node is connected to itself to form the cycle.
Output Format:
The only output line contains the linked list after removing the loop if present.
1 <= N <= 100000.
1 <= ‘VAL’ <= 1000 .
Time limit: 1 sec
6 2
1 2 3 4 5 6
1 2 3 4 5 6
For the given input linked list, the last node is connected to the second node as:
Now, after detecting and removing this loop the linked list will be:
Think of checking each node as the starting point for the cycle.
We are going to have two loops outer-loop and inner-loop
O(N*N), where N is the total number of nodes.
For every iteration of outer-loop we are iterating the linked-list again.
O(1), As we are not using any memory to store anything.