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Problem of the day

You are given an unsorted array/list 'ARR' of 'N' integers. Your task is to return the length of the longest consecutive sequence.

The consecutive sequence is in the form ['NUM', 'NUM' + 1, 'NUM' + 2, ..., 'NUM' + L] where 'NUM' is the starting integer of the sequence and 'L' + 1 is the length of the sequence.

Note:

```
If there are any duplicates in the given array we will count only one of them in the consecutive sequence.
```

```
For the given 'ARR' [9,5,4,9,10,10,6].
Output = 3
The longest consecutive sequence is [4,5,6].
```

```
Can you solve this in O(N) time and O(N) space complexity?
```

Detailed explanation

```
The first line of input contains a single integer 'T', representing the number of test cases or queries to be run. Then the 'T' test cases follow.
The first line of each test case contains integer 'N' denoting the size of the array.
The second line of each test case contains 'N' single space-separated integers, elements of the array.
```

```
For each test case, print an integer in a single line that represents the length of the longest consecutive sequence.
```

```
You are not required to print the expected output; it has already been taken care of. Just implement the function.
```

```
1 <= T <= 10
1 <= N <= 10^5
-10^9 <= ARR[i] <= 10^9
Time Limit: 1 sec
```

```
1
5
33 20 34 30 35
```

```
3
```

```
The longest consecutive sequence is [33, 34, 35].
```

```
1
7
1 9 3 10 4 20 2
```

```
4
```

```
The consecutive sequence is in the form ['NUM', 'NUM' + 1, 'NUM' + 2,...,'NUM' + 'L']. So in the given array, the longest consecutive sequence is [1,2,3,4] where 'NUM' = 1 and 'L' = 3. And the length of the sequence will be 'L' + 1 = 4.
```