# One Odd Occurring

Easy
0/40
Average time to solve is 13m
Contributed by

## Problem statement

Given an array ‘ARR’ of ‘N’ integers, where all the elements occur an even number of times and only one number occurs an odd number of times.

Find and return the number which occurs an odd number of times.

For example:
``````'N' = 5, 'ARR' = [1, 2, 3, 2, 3]
Output: 1

Except for number 1, all numbers occur an even number of times.
``````
Detailed explanation ( Input/output format, Notes, Images )
Input Format :
``````The first line contains a single integer, 'N', representing the size of the array.

The second line contains 'N' space-separated integers.
``````
Output format :
``````The only line contains a single integer representing the number occurring odd number of times.
``````
Note :
``````You don't need to print anything. It has already been taken care of. Just implement the given function.
``````
##### Sample Input 1 :
``````9
4 5 6 5 6 9 9 4 4
``````
##### Sample Output 1 :
``````4
``````
##### Explanation Of Sample Input 1 :
``````5, 6, and 9 occur an even number of times, and only 4 occur odd number of times.
``````
##### Sample Input 2 :
``````5
1 1 1 1 1
``````
##### Sample Output 2 :
``````1
``````
##### Constraints :
``````1 <= 'N' <= 10^5

1 <= 'ARR[i]' <= 10^5

Time Limit: 1 sec
``````
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