# Reconstruct Itinerary

Moderate
0/80
Average time to solve is 15m
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## Problem statement

You are given a matrix of flight 'TICKETS', where the 'i'th row represents 'i’th flight ticket. 'TICKETS'[i] = [SOURCE, DESTINATION] represents that there is a one-way flight starting from the city 'SOURCE' and ending at city 'DESTINATION'. All the flight tickets belong to a man who is initially in city "DEL".

You are supposed to reconstruct the journey satisfying the following conditions:

1. He should begin his journey from “DEL”.

2. He should use all the tickets and complete the journey.

3. He must use all the tickets only once.

Note:
``````1. Journey means the order in which the cities will be visited.

2. The given tickets have at least one itinerary.

3. If multiple valid itineraries are possible, then return the itinerary that is a lexicographically smallest itinerary.
``````
Detailed explanation ( Input/output format, Notes, Images )
Constraints:
``````1 <= T <= 50
1 <= N <= 20000
0 <= M <= 20000
TICKET[i][0] != TICKET[i][1], for any valid 'i'.

Where 'M' denotes the size of the given matrix ‘TICKET’.

Time Limit: 1 sec
``````
Sample Input 1:
``````1
3
DEL KUL
DEL NRT
NRT DEL
``````
Sample Output 1:
``````DEL NRT DEL KUL
``````
Explanation for Sample Input 1:
``````In test case 1, there are three flight tickets.

Source    -     Destination
DEL     -       KUL
DEL      -  NRT
NRT    -     DEL

In order to satisfy all the conditions, he should start from “DEL”, as per the problem statement, use ticket 2, go to “NRT”. Then come back to “DEL” using ticket 3. And then go to “KUL” using ticket 1. So the Itinerary which is possible in this case is DEL -> NRT -> DEL -> KUL.
``````
Sample Input 2:
``````1
2
DEL ATL
ATL DEL
``````
Sample Output 1:
``````DEL ATL DEL
``````
Explanation for Sample Input 2:
``````In test case 1, there are two flight tickets.

Source  -   Destination
DEL     -    ATL
ATL     -    DEL

In order to satisfy all the conditions, he should start from “DEL”, as per the problem statement, use ticket 1, go to “ATL”. Then come back to “DEL” using ticket 2. So the Itinerary which is possible in this case is DEL -> ATL -> DEL.
``````
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