Software Engineer

The problem can be solved by counting the frequency of elements separated by a distance K and finding the number that appears the maximum number of times. Follow the steps below to solve the problem:

1. Initialize a variable ans to store the result.
2. Iterate in the range [0, K-1] using the variable i.
3. Create a map freq to store the frequency of elements separated by a distance of K, starting from i.
4. Traverse the map and find the element that occurs the maximum number of times.
5. Traverse the map again, and if the element is not equal to the maximum occurring element, add its frequency to ans.
6. Print the value of ans as the result.

A for loop was used for this question.
The outer loop iterates over the rows from i = 0 to i = n - 1.
The first inner loop controls the number of white spaces printed on each row, which increases as i increases.
The second inner loop controls the number of stars (*) (or numbers/characters) printed on each row, which decreases as i increases.

The steps to solve the problem using this approach are as follows:

1. Initialize two pointers, i and j, to 0 and 1 respectively. These pointers will help us keep track of the current indices of the elements in the array that we are processing.
2. Loop through the array until either i or j reaches the end of the array.
3. If the element at index i is odd and the element at index j is even, swap them. This ensures that the even number is placed at an even index and the odd number at an odd index.
4. Increment both i and j by 2 to move them to the next odd and even indices, respectively.
5. If the element at index i is already even, increment i by 2.
6. Similarly, if the element at index j is already odd, increment j by 2.
7. Once we have looped through the entire array, the even numbers will be at even indices and the odd numbers at odd indices.
8. Return the modified array.