SDE - 1

Given an array/list of length ‘n’, where the array/list represents the boards and each element of the given array/list represents the length of each board. Some ‘k’ numbers of painters are available to paint these boards. Consider that each unit of a board takes 1 unit of time to paint.

You are supposed to return the area of the minimum time to get this job done of painting all the ‘n’ boards under a constraint that any painter will only paint the continuous sections of boards.

Example :

Input: arr = [2, 1, 5, 6, 2, 3], k = 2

Output: 11

Explanation:
First painter can paint boards 1 to 3 in 8 units of time and the second painter can paint boards 4-6 in 11 units of time. Thus both painters will paint all the boards in max(8,11) = 11 units of time. It can be shown that all the boards can't be painted in less than 11 units of time.

You are given two Singly Linked Lists of integers, which may have an intersection point.

Your task is to return the first intersection node. If there is no intersection, return NULL.

Example:-

The Linked Lists, where a1, a2, c1, c2, c3 is the first linked list and b1, b2, b3, c1, c2, c3 is the second linked list, merging at node c1.

You are given a string S which represents a number. You have to find the smallest number strictly greater than the given number which contains the same set of digits as of the original number i.e the frequency of each digit from 0 to 9 should be exactly the same as in the original number.

For example:

If the given string is 56789, then the next greater number is 56798. Note that although 56790 is also greater than the given number it contains 1 '0' which is not in the original number and also it does not contain the digit '8'.

Note:

The given string is non-empty.

If the answer does not exist, then return -1.

The given number does not contain any leading zeros.