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ARR = [1,2,3,4]
Minimums of window size 1 = min(1), min(2), min(3), min(4) = 1,2,3,4
Maximum among (1,2,3,4) is 4
Minimums of window size 2 = min(1,2), min(2,3), min(3,4) = 1,2,3
Maximum among (1,2,3) is 3
Minimums of window size 3 = min(1,2,3), min(2,3,4) = 1,2
Maximum among (1,2) is 2
Minimums of window size 4 = min(1,2,3,4) = 1
Maximum among them is 1
The output array should be [4,3,2,1].






- An encoded string will be of the form <count>[encoded_string], where the 'encoded_string' inside the square brackets is being repeated exactly 'count' times. Note that 'count' is guaranteed to be a positive integer and can be greater than 9.
- There are no extra white spaces and square brackets are well-formed.
Input: 2[a]
“a” is encoded 2 times, hence the decoded string will be "aa".
Input: 3[a2[b]]
“b” is encoded 2 times, which decodes as 3[abb]. Now, "abb" is encoded 3 times, hence decoded string will be "abbabbabb".



If edges[i][j] = 1, that implies there is a bi-directional edge between ‘i’ and ‘j’, that means there exists both edges from ‘i’ to ‘j’ and to ‘j’ to ‘i’.
Given:
‘N’ = 3
‘edges’ = [[0, 1, 1], [0, 0, 1], [0,0,0]].




1. Horizontally as 1x2 tile
2. Vertically as 2x1 tile
The number of ways might be large so output your answer modulo 10^9 + 7.

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What is recursion?