SDE - 1

A thief is robbing a store and can carry a maximum weight of ‘W’ into his knapsack. There are 'N' items available in the store and the weight and value of each item is known to the thief. Considering the constraints of the maximum weight that a knapsack can carry, you have to find the maximum profit that a thief can generate by stealing items.

Note: The thief is not allowed to break the items.

For example, N = 4, W = 10 and the weights and values of items are weights = [6, 1, 5, 3] and values = [3, 6, 1, 4]. Then the best way to fill the knapsack is to choose items with weight 6, 1 and 3. The total value of knapsack = 3 + 6 + 4 = 13.

You are given a binary tree with ‘N’ nodes.

Your task is to find the “Maximum Path Sum” for any path.

Note :

1. A ‘path’ is a sequence of adjacent pair nodes with an edge between them in the binary tree.
2. The ‘path’ doesn’t need to pass through the root.
3. The ‘path sum’ is the sum of the node’s data in that path.