EGIL - Ericsson Global India Limited interview experience Real time questions & tips from candidates to crack your interview
Software Developer
EGIL - Ericsson Global India Limited
2 rounds | 2 Coding
problems
Selected Interview preparation journey
Journey
I applied in Ericsson Company on LinkedIn for software developer profile and got shortlisted for the interview.
Total interview rounds: 2
There are 2 technical rounds and hr round which you need to clear in order to get into the company.
Application story
I applied on LinkedIn and got shortlisted for the first interview which went for 1 hr next day I got the news that I have another round 2 days later I went for another round and got shortlisted for the Hr discussion and got the offer.
Why selected/rejected for the role?
I got shortlisted because I was consistently preparing for the role and working on my fundamentals and core learning, also basic coding questions I was practising. Java 8 is must with good knowledge of Threading.
Preparation
Duration: 3 Months
Topics: Data Structures, Algorithms, Java 8, Sql, Spring Boot
Tip 1 : Prepare fundamental theory well
Tip 2 : Prepare Easy and medium level questions
Tip 3 : Go through you resume well
Application process
Where: Other
Eligibility: Bachelor’s degree or higher in ECE, IT, CS or MCA.
Tip 1 : Make your resume relevant
Tip 2 : Mention projects
Interview rounds
01
Round
Medium
Online Coding Interview
Duration60 Minutes
Interview date14 Dec 2021
Coding problem1
1. Valid Parentheses
Easy
10m average time
80% success
0/40
Asked in companies
You're given a string 'S' consisting of "{", "}", "(", ")", "[" and "]" .
Return true if the given string 'S' is balanced, else return false.
For example:
'S' = "{}()".
There is always an opening brace before a closing brace i.e. '{' before '}', '(' before ').
So the 'S' is Balanced.
Problem approach
Stack st = new Stack<>();
for(int i=0; i if(!st.isEmpty() && s.charAt(i)==')' && st.peek()=='(') st.pop();
else if(!st.isEmpty() && s.charAt(i)=='}' && st.peek()=='{') st.pop();
else if(!st.isEmpty() && s.charAt(i)==']' && st.peek()=='[') st.pop();
else st.push(s.charAt(i));
}
return st.isEmpty();
02
Round
Easy
Online Coding Interview
Duration60 Minutes
Interview date16 Dec 2022
Coding problem1
1. Merge Two Sorted Linked Lists
Moderate
15m average time
80% success
0/80
Asked in companies
You are given two sorted linked lists. You have to merge them to produce a combined sorted linked list. You need to return the head of the final linked list.
Note:
The given linked lists may or may not be null.
For example:
If the first list is: 1 -> 4 -> 5 -> NULL and the second list is: 2 -> 3 -> 5 -> NULL
The final list would be: 1 -> 2 -> 3 -> 4 -> 5 -> 5 -> NULL
Problem approach
ListNode ans = new ListNode(0);
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
if(list1 == null) return list2;
if(list2 == null) return list1;
if(list1.val<=list2.val){
list1.next = mergeTwoLists(list1.next, list2);
return list1;
} else{
list2.next = mergeTwoLists(list1, list2.next);
return list2;
}
}
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