SDE - 1

You are given an Integer array ‘ARR’ and an Integer ‘K’.

Your task is to find the ‘K’ most frequent elements in ‘ARR’. Return the elements in any order.

For Example:

You are given ‘ARR’ = {1, 2, 2, 3, 3} and ‘K’ = 2. 

The answer will {2, 3} as 2 and 3 are the elements occurring most times.

You have been given a Binary Tree of integers.

Your task is to print the Right view of it.

The right view of a Binary Tree is a set of nodes visible when the tree is viewed from the Right side and the nodes are printed from top to bottom order.

You are given an integer array 'arr' of size 'N' and an integer 'K'.

Your task is to find the total number of subarrays of the given array whose sum of elements is equal to k.

A subarray is defined as a contiguous block of elements in the array.

Example:

Input: ‘N’ = 4, ‘arr’ = [3, 1, 2, 4], 'K' = 6

Output: 2

Explanation: The subarrays that sum up to '6' are: [3, 1, 2], and [2, 4].

Given an array/list of length ‘n’, where the array/list represents the boards and each element of the given array/list represents the length of each board. Some ‘k’ numbers of painters are available to paint these boards. Consider that each unit of a board takes 1 unit of time to paint.

You are supposed to return the area of the minimum time to get this job done of painting all the ‘n’ boards under a constraint that any painter will only paint the continuous sections of boards.

Example :

Input: arr = [2, 1, 5, 6, 2, 3], k = 2

Output: 11

Explanation:
First painter can paint boards 1 to 3 in 8 units of time and the second painter can paint boards 4-6 in 11 units of time. Thus both painters will paint all the boards in max(8,11) = 11 units of time. It can be shown that all the boards can't be painted in less than 11 units of time.