Software Engineer

Reverse the given string word wise. That is, the last word in given string should come at 1st place, last second word at 2nd place and so on. Individual words should remain as it is.

Given an array 'A' consisting of 'N' integers, find the smallest subarray of 'A' containing exactly 'K' distinct integers.

Note :

If more than one such contiguous subarrays exist, consider the subarray having the smallest leftmost index.

For example - if A is [1, 2, 2, 3, 1, 3 ] and k = 2 then the subarrays: [1,2], [2,3], [3,1], [1,3] are the smallest subarrays containing 2 distinct elements. In this case, we will consider the starting and ending index of subarray [1,2] i.e. 0 and 1.

You are given a paragraph that may have letters both in lowercase and uppercase, spaces, and punctuation. You have also given a list of banned words. Now your task is to find the most frequent word which is not in the list of banned words. There will always be a solution, and the solution will be unique.

While comparing words, you can ignore whether the letter is lowercase or uppercase. For example, ‘AsK’ and ‘aSK’ are the same. The words will always contain only alphabets or we can say words will be separated by spaces or punctuation. The answer will be in uppercase letters.

The words in the banned list will always be in upper letters and free from punctuation and spaces.

For example :

Paragraph = ‘It's a square SqUare. It's a FLAT flat.’ 
Banned =[FLAT, IT, S]. 
So we can see these words [IT, S, SQUARE, FLAT ]  are most frequent.
Now we will look at to banned list and we can see 3 of the words are banned.
So we have a unique answer SQUARE which has a frequency of 2 and not on the banned list.

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