Software Engineer

Print the following pattern

Pattern for N = 4

Hint

As taught in the video, you just have to modify the code so that instead of printing numbers, it should output stars ('*').

The dots represent spaces.

You are given a Circular Linked List of integers, and an integer, 'key'.

You have to write a function that finds the given key in the list and deletes it. If no such key is present, then the list remains unchanged.

For Example :

This is a visualization of the Circular Linked List, represented by:
1 2 3 4 5 -1

Note :

The Circular Linked List before/after deletion may happen to be empty. In that case, only print -1.

All integers in the list are unique.

Given two strings ‘STR’ and ‘PTR’. Find all the starting indices of ‘PTR’ anagram substring in ‘STR’. Two strings are anagram if and only if one string can be converted into another string by rearranging the character.

For example, ‘ABCD’ and ‘ACBD’ are two anagram strings because ‘ACBD’ can be converted into ‘ABCD’ by rearranging the ‘B’ and ‘C’. ’ABA’ and ‘ABB’ are not anagram because we can’t convert ‘ABA’ to ‘ABB’ by rearranging the characters of particular strings.

‘ABACD’ and ‘CABAD’ are anagram because ‘ABACD’ can be converted into ‘CABAD’ by rearranging the first ‘A’ with ‘C’ and second ‘A’ with ‘B’.

Note:

Strings ‘STR’ and ‘PTR’ consist only of English uppercases.

Length of string ‘STR’ will always be greater than or equal to the length of string ‘PTR’.

The index is ‘0’ based.

In case, there is no anagram substring then return an empty sequence.

Explanation:

For example, the given ‘STR’ is ‘BACDGABCD’ and ‘PTR’ is ‘ABCD’. Indices are given

0-3 in ‘STR’ index 0,1,2,3 are ‘BACD’ and it is an anagram with ‘ABCD’
1-4 in ‘STR’ index 1,2,3,4 are ‘ACDG’ and it is not anagram with ‘ABCD’
2-5 in ‘STR’ index 2,3,4,5 are ‘CDGA’ and it is not anagram with ‘ABCD’
3-6 in ‘STR’ index 3,4,5,6 are ‘DGAB’ and it is not anagram with ‘ABCD’
4-7 in ‘STR’ index 4,5,6,7 are ‘GABC’ and it is not anagram with ‘ABCD’
5-8 in ‘STR’ index 5,6,7,8 are ‘ABCD’ and it is an anagram with ‘ABCD’

Hence there are 2 starting indices of substrings in the string ‘STR’ that are anagram with given ‘PTR’  which are index 0 and 5.

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