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Tip 3: Prepare through mock interviews to practice explaining your approach while solving problems in an actual interview.
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Below is the example showing the input tree and its sum tree.

Do a traversal of the given tree. In the traversal, store the old value of the current node, recursively call for the left and right subtrees, and change the value of the current node to the sum of the values returned by the recursive calls. Finally, return the sum of the new value and the old value (which is the sum of the values in the subtree rooted at this node).



There are two possible cases for every node:
The node’s key is outside the given range. This case has two sub-cases: a) The node’s key is smaller than the minimum value. b) The node’s key is greater than the maximum value.
The node’s key is within the range.
We don’t need to do anything for case 2.
In case 1, we need to remove the node and change the root of the subtree rooted at this node. The idea is to fix the tree in a post-order fashion. When we visit a node, we ensure that its left and right subtrees are already fixed. In case
1.a), we simply remove the root and return the right subtree as the new root. In case
1.b), we remove the root and return the left subtree as the new root.



Input: Consider the following Binary Tree:
Output:
Following is the level-order traversal of the given Binary Tree: [1, 2, 3, 5, 6, 4]
We can use a queue just like we did in Level Order Traversal. However, in this case, we can also maintain a flag variable that keeps track of the alternate level to reverse the order of the corresponding level traversal. flag == true implies that we have to insert from left to right, and flag == false means we have to insert elements from right to left in our answer vector.



Let the array = [ 4, 2, 1, 5, 3 ]
Let pivot to be the rightmost number.

It is a straight forward sorting algorithm.



For given 2D array :
[ [ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ] ]
After 90 degree rotation in anti clockwise direction, it will become:
[ [ 3, 6, 9 ],
[ 2, 5, 8 ],
[ 1, 4, 7 ] ]



Infix expression: A + B * C - D
Postfix expression: A B + C D - *
1. Operators will only include the basic arithmetic operators like '*', '/', '+', and '-'.
2. The operand can contain multiple digits.
3. The operators and operands will have space as a separator between them.
4. There won’t be any brackets in the postfix expression.
An expression is called a postfix expression if the operator appears in the expression after the operands.

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What is recursion?