Tip 1 : Be consistent, practice regularly whatever you read/study.
Tip 2 : Apply what you learn through code.
Tip 1 : Have some projects on your resume.
Tip 2 : If you have an internship or training explain it in a proper way like what are the techniques you learned during your training.



1. You can return the list of values in any order. For example, if a valid triplet is {1, 2, -3}, then {2, -3, 1}, {-3, 2, 1} etc is also valid triplet. Also, the ordering of different triplets can be random i.e if there are more than one valid triplets, you can return them in any order.
2. The elements in the array need not be distinct.
3. If no such triplet is present in the array, then return an empty list, and the output printed for such a test case will be "-1".



1. A magic index in an array A[0 ... N - 1] is defined to be an index i such that A[i] = i.
2. The elements in the array can be negative.
3. The elements in the array can be repeated multiple times.
4. There can be more than one magic index in an array.



If the dictionary consists of the following words:-
["caa", "aaa", "aab"], and 'K' is 3.
Then, the order of the alphabet is -
['c', 'a', 'b']
If the language consists of four letters, the four letters should be the starting four letters of the English language.
However, their order might differ in the alien language.



2, 23, and 4343456 are Jumping numbers but 296 and 89498 are not.
The difference between ‘9’ and ‘0’ is not considered as 1. All single-digit numbers are considered as Jumping Numbers.



If the array of strings is: {co, code, studio, codingninjas, coding, debug, coder, cipher}
Then the original cost of the array is 2 + 4 + 6 + 12 + 6 + 5 + 5 + 6 = 46.
If we select the new string as “cod” and delete the matching prefixes if exists then the array becomes: {co, e, studio, ingninjas, ing, debug, er, cipher}, and the cost now becomes: 2 + 1 + 6 + 9 + 3 + 5 + 2 + 6 = 34.
You can check for any other possible string, the cost will not become less than 34, hence the optimal answer for this case is “cod”.
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