R&D Intern

You have been given a Binary Tree of integers, find the minimum depth of this Binary Tree. The minimum depth of a Binary Tree is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Note:

A leaf is a node with no children.

For example:

For the given binary tree

Output: 2
The shortest path is from root node 1 to leaf node 2 which contains 2 nodes in the path. Hence, the minimum depth is 2.

You are given an integer N. Your task is to return a 2-D ArrayList containing the pascal’s triangle till the row N.

A Pascal's triangle is a triangular array constructed by summing adjacent elements in preceding rows. Pascal's triangle contains the values of the binomial coefficient. For example in the figure below.

For example, given integer N= 4 then you have to print.

1  
1 1 
1 2 1 
1 3 3 1

Here for the third row, you will see that the second element is the summation of the above two-row elements i.e. 2=1+1, and similarly for row three 3 = 1+2 and 3 = 1+2.

You are given a list of a repeated set of integers. Your task for the problem is to return a list of the given elements in decreasing sorted order of their frequency of repetition in the given list with the element with the highest frequency of repetition first and so on.

Note :

If two numbers have the same frequency then keep the one that was present before the other in the original given list (array) first.

For Example :

Input:  arr[] = {2, 5, 2, 8, 5, 6, 8, 8}
Output: arr[] = {8, 8, 8, 2, 2, 5, 5, 6}

Explanation :
When you sort the array based on the decreasing order of the frequency of repetition of integers in the original array, 
you’ll find that the element ‘8’ is the integer with the most repeated values therefore it would be arranged first after which since both 2 and 5 have the same number of repeated 
values in the original array but since the 2 arrived first so we will first arrange 2 and then 5 in our resultant array, while would be the last element after sorting here.

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