Tip 1 : Regarding DSA preparation, I have a theory. 20 percent of the questions will be asked in 80 percent of the interview and 80 percent of the questions will be asked in 20 percent of the interviews. In short, some questions have a very high chance of coming up during the interviews and some have very low chance. We should focus more on the questions that have more chance of coming up in the interview. You can find these questions on Striver SDE Sheet, InterviewBit, Leetcode 100 most liked, Leetcode 100 most important.
Tip 2 : Try to find patterns in the questions. Group them according to a pattern for better understanding. Make notes in Excel, word or hand written and revise them.
Tip 3 : Try to solve the questions that have more chance of coming up in the interview with many different approaches.
Tip 1 : Make Sure that your resume is simple and also try to fit all the information on only one page.
Tip 2 : Have at least 2 projects with the latest technologies, Github link of projects should be provided



A subarray is a contiguous block of elements that can be formed by deleting some (possibly zero) elements from the beginning or the end of the original array.
If the given array is [1, 2, 3, 4, 5], then [2, 3, 4], [1, 2], [5] are some subarrays while [1, 3], [2, 3, 5] are not.
If there are multiple subarrays with minimum length, find one which appears earlier in the array (i.e. subarray that starts with lower index).
If there is no such subarray, print an empty line.
You have been given an array(ARR) of positive integers and an integer X. You have to find the minimum length subarray such that the sum of all of its elements is strictly greater than the given integer X.



For a given string “BaaB”
3 possible palindrome partitioning of the given string are:
{“B”, “a”, “a”, “B”}
{“B”, “aa”, “B”}
{“BaaB”}
Every substring of all the above partitions of “BaaB” is a palindrome.
You are given a string 'S'. Your task is to partition 'S' such that every substring of the partition is a palindrome. You need to return all possible palindrome partitioning of 'S'.
Note: A substring is a contiguous segment of a string.


In lexicographical order, cell (a, b) comes before cell (c, d), if either a < c or (a = c and b < d).
You are given an n×n chessboard. Rows and columns of the board are numbered from 0 to ‘n’-1. Cell (r,c) lies at the intersection of row number 'r' and column number ‘c’.



1. To implement means you need to complete some predefined functions, which are supported by a normal queue such that it can efficiently handle the given input queries which are defined below.
2. The implemented queue must support the following operations of a normal queue:
a. enQueue(data) : This function should take one argument of type integer and place the integer to the back of the queue.
b. deQueue(): This function should remove an integer from the front of the queue and also return that integer. If the queue is empty, it should return -1.
c. peek(): This function returns the element present in the front of the queue. If the queue is empty, it should return -1.
d. isEmpty(): This function should return true if the queue is empty and false otherwise.
3. You will be given q queries of 4 types:
a. 1 val - For this type of query, you need to insert the integer val to the back of the queue.
b. 2 - For this type of query, you need to remove the element from the front of the queue, and also return it.
c. 3 - For this type of query, you need to return the element present at the front of the queue(No need to remove it from the queue).
d. 4 - For this type of query, you need to return true if the queue is empty and false otherwise.
4. For every query of type:
a. 1, you do not need to return anything.
b. 2, return the integer being deQueued from the queue.
c. 3, return the integer present in the front of the queue.
d. 4, return “true” if the queue is empty, “false” otherwise.
Operations:
1 5
1 10
2
3
4
Enqueue operation 1 5: We insert 5 at the back of the queue.
Queue: [5]
Enqueue operation 1 10: We insert 10 at the back of the queue.
Queue: [5, 10]
Dequeue operation 2: We remove the element from the front of the queue, which is 5, and print it.
Output: 5
Queue: [10]
Peek operation 3: We return the element present at the front of the queue, which is 10, without removing it.
Output: 10
Queue: [10]
IsEmpty operation 4: We check if the queue is empty.
Output: False
Queue: [10]
Implement a queue data structure which follows FIFO(First In First Out) property, using only the instances of the stack data structure.

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To make an AI less repetitive in a long paragraph, you should increase: