Tip 1: Practice BFS, DFS, and shortest path techniques like Dijkstra's and A* for solving connectivity and optimization problems.
Tip 2: Learn scalable architecture principles like caching, load balancing, and database sharding.
Tip 3: Break problems into reusable functions or classes for better readability, maintainability, and testing.
Tip 1: Add factual information about the projects you’ve made.
Tip 2: State only the skills you possess, not the ones you don’t.



You are given arr = {1, 3, 8, 6, 7}, then our answer will be 3.
Sorted form of arr = {1, 3, 6, 7, 8}. The maximum absolute difference between two consecutive elements is 6 - 3 = 3, which is the correct answer.
Array: [2, 3, 10, 6, 4, 8, 1]
Start with min_element = 2 (first element) and max_difference = -1.
Compare the next element (3) with min_element. The difference is 3 - 2 = 1. Update max_difference = 1.
Next, compare 10 with min_element. The difference is 10 - 2 = 8. Update max_difference = 8.
Continue with 6, 4, and 8. None of these update min_element, and their differences do not exceed max_difference.
Lastly, 1 becomes the new min_element, but since it's the last element, no further updates occur.
Final Result: The maximum difference is 8.



Array: [3, 4, -1, 1]
Segregate positive numbers from negatives by swapping. After segregation: [3, 4, 1, -1].
Use index marking to identify present numbers.
Mark the index corresponding to each positive number. For 3, mark index 2 (array[2] = -array[2]). Array becomes [3, 4, -1, -1].
Mark for 4 (out of bounds, skip). Mark for 1: array[0] = -array[0]. Array becomes [-3, 4, -1, -1].
Traverse the array to find the first missing positive.
Index 0 is negative, so 1 is present. Index 1 is positive, indicating 2 is missing.
Final Result: The smallest missing positive integer is 2.



Let the array 'ARR' be [1, 2, 3] and 'B' = 5. Then all possible valid combinations are-
(1, 1, 1, 1, 1)
(1, 1, 1, 2)
(1, 1, 3)
(1, 2, 2)
(2, 3)
Array: [1, 2, 2, 3, 4, 4]
Steps:
Create an empty set unique_elements.
Iterate through the array:
Add 1 to the set → unique_elements = {1}.
Add 2 to the set → unique_elements = {1, 2}.
Skip duplicate 2.
Add 3 to the set → unique_elements = {1, 2, 3}.
Add 4 to the set → unique_elements = {1, 2, 3, 4}.
Skip duplicate 4.
Calculate the sum of unique_elements: 1 + 2 + 3 + 4 = 10.
Final Result: The sum of unique elements is 10.

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What is recursion?