Tip 1: Learn common algorithms that heavily rely on data structures, such as sorting, searching, and graph traversal algorithms.
Tip 2: Understand how data structures play a crucial role in the efficiency of these algorithms.
Tip 1: Include some projects on your resume.
Tip 2: Avoid putting false information on your resume.
Apart from DSA, computer networking, and DBMS, we were presented with C++ questions focusing on topics like memory management, pointers, templates, exception handling, and file handling. We were assessed on our understanding of these concepts and our ability to write clean and efficient C++ code.



1. The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).
2. Output the paths in the order in which they exist in the tree from left to right. Example: In the below example, path {1,3} is followed by {3,1} and so on.
For K = 4 and tree given below:

The possible paths are:
1 3
3 1
-1 4 1
4
-1 5
The sum of values of nodes of each of the above-mentioned paths gives a sum of 4.
The idea is simple: record all prefix sums in a hash table along the path. For current prefix sum x, check if (x - target)
appears in the hash table.



Let’s say we have n=4 nodes, 'LEFT_CHILD' = {1, -1, 3, -1} and
RIGHT_CHILD = {2, -1, -1, -1}. So the resulting tree will look like this:
It will return True as there is only one valid binary tree and each node has only one parent and there is only one root.



[1, 2, 3, 4] is a strictly increasing array, while [2, 1, 4, 3] is not.
Approach 1 (Naive Solution) :.



Input: 'a' = [7, 12, 1, 20]
Output: NGE = [12, 20, 20, -1]
Explanation: For the given array,
- The next greater element for 7 is 12.
- The next greater element for 12 is 20.
- The next greater element for 1 is 20.
- There is no greater element for 20 on the right side. So we consider NGE as -1.
Approach 1 (Naive Solution):
1. Use two loops: the outer loop picks all the elements one by one.
2. The inner loop looks for the first greater element for the element picked by the outer loop.
3. If a greater element is found, then that element is printed as the next; otherwise, -1 is printed.

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What is recursion?