SDE - 2

I wrote C++as skill, So interviewer asked me how you make sure that whenever dynamically memory is allocated, it gets freed up when you go out of scope from the place where you allocated the memory?

You are given an array 'a' of size 'n'.

Print the Next Greater Element(NGE) for every element.

The Next Greater Element for an element 'x' is the first element on the right side of 'x' in the array, which is greater than 'x'.

If no greater elements exist to the right of 'x', consider the next greater element as -1.

For example:

Input: 'a' = [7, 12, 1, 20]

Output: NGE = [12, 20, 20, -1]

Explanation: For the given array,

- The next greater element for 7 is 12.

- The next greater element for 12 is 20. 

- The next greater element for 1 is 20. 

- There is no greater element for 20 on the right side. So we consider NGE as -1.

Given a linked list having two pointers in each node. The first one points to the next node of the list, however, the other pointer is random and can point to any node of the list or null. The task is to create a deep copy of the given linked list and return its head. We will validate whether the linked list is a copy of the original linked list or not.

A deep copy of a Linked List means we do not copy the references of the nodes of the original Linked List rather for each node in the original Linked List, a new node is created.

For example,

Random pointers are shown in red and next pointers in black.

You are given two strings S and X containing random characters. Your task is to find the smallest substring in S which contains all the characters present in X.

Example:

Let S = “abdd” and X = “bd”.

The windows in S which contain all the characters in X are: 'abdd', 'abd', 'bdd', 'bd'. 
Out of these, the smallest substring in S which contains all the characters present in X is 'bd'. 
All the other substring have a length larger than 'bd'.

A binary tree is a tree where each node has at most two children i.e left child and right child.

You are given a binary tree, where the structure of the node is as follow -:

class BinaryTreeNode {
 int data;      // Value of the node.
 BinaryTreeNode *left;  // Pointer to left child node.
 BinaryTreeNode *right; // Pointer to right child node.
 BinaryTreeNode *next;  // Pointer to next right node at same level. 
}

Your task is to connect all the adjacent nodes at the same level in the given binary tree. You can do this by populating each 'next' pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL. Initially, all the next pointers are set to NULL.

For Example:

Consider the figure shown below. The left part represents the initial binary tree and right part represents the binary tree after connecting adjacent nodes at the same level.

In the tree shown in the picture above -:
The ‘next’ pointer of the node having value 2 is connected to the node having value 3.
The ‘next’ pointer of the node having value 4 is connected to the node having value 5.
The ‘next’ pointer of the node having value 5 is connected to the node having value 6.
The ‘next’ pointer of nodes having value 1, 3, 6 will have a value NULL as there are no next right nodes in their cases.

Note:

1. The structure of the ‘Node’ of a binary tree is already defined. You should not change it.   
2. The root of the binary tree is known to you.  
3. There is at least one node in the given binary tree.
4. You may only use constant extra space.

You have been given a string ‘S' representing a number. Your task is to find the closest palindromic number from this integer represented by 'S'. The closest number is defined as the one for which the absolute difference between the given integer represented by 'S' and the palindrome number is minimum. If more than one number have the same difference then return the smaller integer.

Example:

Let 'S' is 121. Then the nearest integers are 111 and 131 which are palindrome. Both have the same absolute difference but 111 is smaller. Hence 111 is the answer.

Here Interviewer asked me to write multiple producers and multiple consumers problem.
Also how you can increase performance of the system

You are given two strings 'str1' and 'str2'. Find the minimum operations required to convert str1 into str2.

An Operation is defined as:

A character from an index of a string(str1) is put at the end of it, is defined as a single operation.

 Note :

You cannot perform any operation on the string, str2.

You have been given a Snake and Ladder Board with 'N' rows and 'N' columns with the numbers written from 1 to (N*N) starting from the bottom left of the board, and alternating direction each row.

For example

For a (6 x 6) board, the numbers are written as follows:

You start from square 1 of the board (which is always in the last row and first column). On each square say 'X', you can throw a dice which can have six outcomes and you have total control over the outcome of dice throw and you want to find out the minimum number of throws required to reach the last cell.
Some of the squares contain Snakes and Ladders, and these are possibilities of a throw at square 'X':
You choose a destination square 'S' with number 'X+1', 'X+2', 'X+3', 'X+4', 'X+5', or 'X+6', provided this number is <= N*N.
If 'S' has a snake or ladder, you move to the destination of that snake or ladder.  Otherwise, you move to S.
A board square on row 'i' and column 'j' has a "Snake or Ladder" if board[i][j] != -1. The destination of that snake or ladder is board[i][j].

Note :

You can only take a snake or ladder at most once per move: if the destination to a snake or ladder is the start of another snake or ladder, you do not continue moving - you have to ignore the snake or ladder present on that square.

For example, if the board is:
-1 1 -1
-1 -1 9
-1 4 -1
Let's say on the first move your destination square is 2  [at row 2, column 1], then you finish your first move at 4 [at row 1, column 2] because you do not continue moving to 9 [at row 0, column 0] by taking the ladder from 4.

A square can also have a Snake or Ladder which will end at the same cell.
For example, if the board is:
-1 3 -1
-1 5 -1
-1 -1 9
Here we can see Snake/Ladder on square 5 [at row 1, column 1] will end on the same square 5.

High level design of Crawler.

Design a system to save key value pair such a way millions of request coming to save/update a key value and millions of request coming to read the value of key.

Multiple producers will be responsible to write data to a disc and multiple consumers will read data to from the disc.
Producers will publish event that comprizes of {DataSizeInBytes and Data}