Tip 1 : Work on Competitive Programming skills. That is one thing most companies look out for during hiring. Solve at least 100
questions from every topic.
Tip 2 : You should have at least 2 good projects on your resume. Only write the things that you are completely sure of.
Tip 3 : Work on CS fundamentals as well like -OOPS, OS, and DBMS. There will be MCQ questions from this in the coding round as well as in the 1:1 round
Tip 1 : Need at least 2 good projects on the resume. Write a short 2-3 lines summary of the project and the tech stack
used.
Tip 2 : Resume should be 1 page only. Try to keep the Resume short with useful information only.
Tip 3 : Your Resume should clearly mention the skillset you have. Companies sometimes filter out Resume based on
skillset only
It was a pure DSA round. 2 coding questions were asked of medium difficulty. I was able to solve both the questions.



We can take a map and store all the times in it with 'A' and 'D' as value respectively for Arrival time and Departure time. Then sort this map based on keys and iterate the map, if value is 'A' add 1 to the ans otherwise subtract 1. Max value of ans will be the min no. of platforms needed



1. A node will be in the bottom-view if it is the bottom-most node at its horizontal distance from the root.
2. The horizontal distance of the root from itself is 0. The horizontal distance of the right child of the root node is 1 and the horizontal distance of the left child of the root node is -1.
3. The horizontal distance of node 'n' from root = horizontal distance of its parent from root + 1, if node 'n' is the right child of its parent.
4. The horizontal distance of node 'n' from root = horizontal distance of its parent from the root - 1, if node 'n' is the left child of its parent.
5. If more than one node is at the same horizontal distance and is the bottom-most node for that horizontal distance, including the one which is more towards the right.
Input: Consider the given Binary Tree:

Output: 4 2 6 3 7
Explanation:
Below is the bottom view of the binary tree.

1 is the root node, so its horizontal distance = 0.
Since 2 lies to the left of 0, its horizontal distance = 0-1= -1
3 lies to the right of 0, its horizontal distance = 0+1 = 1
Similarly, horizontal distance of 4 = Horizontal distance of 2 - 1= -1-1=-2
Horizontal distance of 5 = Horizontal distance of 2 + 1= -1+1 = 0
Horizontal distance of 6 = 1-1 =0
Horizontal distance of 7 = 1+1 = 2
The bottom-most node at a horizontal distance of -2 is 4.
The bottom-most node at a horizontal distance of -1 is 2.
The bottom-most node at a horizontal distance of 0 is 5 and 6. However, 6 is more towards the right, so 6 is included.
The bottom-most node at a horizontal distance of 1 is 3.
The bottom-most node at a horizontal distance of 2 is 7.
Hence, the bottom view would be 4 2 6 3 7
Its a simple standard tree question
I applied the standard approach
It was a coding round. Two problems from DSA basic level questions were asked in this round. I was able to solve only one, which was obviously the easier one. I was not able to solve second questions



Serialization is the process of translating a data structure or object state into a format that can be stored or transmitted (for example, across a computer network) and reconstructed later. The opposite operation, that is, extracting a data structure from stored information, is deserialization.
I was not able to solve this question.



In the given linked list, there is a cycle, hence we return true.


Here's your problem of the day
Solving this problem will increase your chance to get selected in this company
What is recursion?