Fullstack Developer

You are given two strings 'A' and 'B' of words. Your task is to find out the most frequent and lexicographically smallest word in string 'A', which is not present in string 'B'. If no such word is present in 'A', then return -1.

Note:

1. A word is a sequence of one or more lowercase characters.

2. Words are separated by a single whitespace character.

Example:

For the given string 'A' = “coding ninjas coding ninjas” and 'B' = “data structures and algorithms”, so both the word 'coding' and 'ninjas' are not present in string 'B' and occur two times each, but the word “coding” is lexicographically smaller than the word “ninjas”. So the answer is “coding”.

A Derangement is a permutation of ‘N’ elements, such that no element appears in its original position. For example, an instance of derangement of {0, 1, 2, 3} is {2, 3, 1, 0}, because 2 present at index 0 is not at its initial position which is 2 and similarly for other elements of the sequence.

Given a number ‘N’, find the total number of derangements possible of a set of 'N’ elements.

Note:

The answer could be very large, output answer %(10 ^ 9 + 7).

Sanyam has ‘N’ candies, he wants to distribute that into ‘K’ of his friends. He made his ‘K’ friends stand in line, in increasing order of his likeness. Not being so smart he gives 1 candy to the first friend, 2 to the second person, and so on till the kth person. In the next turn, the first person gets ‘K + 1’ candies, the second person gets ‘K + 2’ candies, and so on.

While distributing the candies, if at a turn, the number of candies to be given to a friend is less than the required candies, then that friend gets all the remaining candies and Sanyam stops the distribution.

Your task is to find the total number of candies every person has at the end.