Software Engineer

I used the iterative approach. The iterative method for reversing a linked list uses three pointers to systematically reverse the direction of links between nodes. We maintain a prev pointer (initially null), a current pointer (starting at the head), and a next pointer to temporarily store the next node before we lose the reference.

The algorithm works by traversing the list once. At each step, we store the next node, reverse the current node's link to point to the previous node instead of the next, and then advance both the prev and current pointers. This process continues until we reach the end of the list, at which point prev becomes the new head of the reversed list.

This method is preferred because it uses constant extra space O(1) and has linear time complexity O(n), making it both memory-efficient and easy to understand.

The recursive method breaks down string reversal into smaller subproblems by processing one character at a time. The base case occurs when the string is empty or has only one character, which is already considered "reversed." For longer strings, we recursively reverse the substring from the second character to the end, then append the first character to the result. Alternatively, we can extract the last character and recursively reverse the remaining substring, then prepend the last character.

While this approach demonstrates elegant problem decomposition and is useful for understanding recursion concepts, it is generally less efficient due to the overhead of multiple function calls and the space used by the call stack—resulting in O(n) space complexity in addition to O(n) time complexity.

I used recursion to solve this question.

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