Nucleus Software interview experience Real time questions & tips from candidates to crack your interview

Associate Software Engineer

Nucleus Software
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2 rounds | 2 Coding problems

Interview preparation journey

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Preparation
Duration: 5 months
Topics: SQL, Java, OOPS, Algorithms, Data Structures (Stack, Queue), Python, Excel
Tip
Tip

Tip 1 : Do at least one good project and have great deep knowledge about your role in the project
Tip 2 : Learn at least one language with advanced knowledge and clear all concepts about that language
Tip 3 : Practice at least 10 questions daily on any other coding site.

Application process
Where: Campus
Eligibility: Above 60℅ in 10th, 12th and Btech. No active backlogs in B. Tech
Resume Tip
Resume tip

Tip 1 : Be clear about what you are writing in your resume. Be truthful. Your interview may totally depend on the resume. It depends on the interviewer. So you should be aware of everything you are writing in your resume. 
Tip 2 : Make your resume worth selecting. Highlight every project and your contribution so far. Add skills you are good at.

Interview rounds

01
Round
Medium
Online Coding Interview
Duration35 minutes
Interview date17 Nov 2022
Coding problem1

1. Closest Sum

Moderate
30m average time
70% success
0/80
Asked in companies
AmazonMicrosoftAcko

Given an array 'ARR'' of 'N' integers and an integer 'target', your task is to find three integers in 'ARR' such that the sum is closest to the target.

Note
In the case of two closest sums, print the smallest sum.
Problem approach

// Simple C++ program to find the pair with sum closest to a given no.
#include 

using namespace std;

// Prints the pair with sum closest to x

void printClosest(int arr[], int n, int x)
{

int res_l, res_r; // To store indexes of result pair


// Initialize left and right indexes and difference between

// pair sum and x

int l = 0, r = n-1, diff = INT_MAX;


// While there are elements between l and r

while (r > l)

{

// Check if this pair is closer than the closest pair so far

if (abs(arr[l] + arr[r] - x) < diff)

{

res_l = l;

res_r = r;

diff = abs(arr[l] + arr[r] - x);

}


// If this pair has more sum, move to smaller values.

if (arr[l] + arr[r] > x)

r--;

else // Move to larger values

l++;

}


cout <<" The closest pair is " << arr[res_l] << " and " << arr[res_r];
}

// Driver program to test above functions

int main()
{

int arr[] = {10, 22, 28, 29, 30, 40}, x = 54;

int n = sizeof(arr)/sizeof(arr[0]);

printClosest(arr, n, x);

return 0;
}

Try solving now
02
Round
Hard
Face to Face
Duration45 minutes
Interview date31 Aug 2021
Coding problem1

1. DBMS Questions

SQL Query to fetch records that are present in one table but not in another table.

Here's your problem of the day

Solving this problem will increase your chance to get selected in this company

Skill covered: Programming

What is recursion?

Choose another skill to practice
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