Tip 1 : Must do Previously asked Interview as well as Online Test Questions.
Tip 2 : Go through all the previous interview experiences from Codestudio and Leetcode.
Tip 3 : Do at-least 2 good projects and you must know every bit of them.
Tip 1 : Have at-least 2 good projects explained in short with all important points covered.
Tip 2 : Every skill must be mentioned.
Tip 3 : Focus on skills, projects and experiences more.
Technical round with 2 DSA problems discussed.



Input: 'list' = [1, 2, 3, 4], 'k' = 2
Output: 2 1 4 3
Explanation:
We have to reverse the given list 'k' at a time, which is 2 in this case. So we reverse the first 2 elements then the next 2 elements, giving us 2->1->4->3.
All the node values will be distinct.


Technical round with 2 DSA problems discussed.



Input: 'arr' = [2, 2, 2, 2, 0, 0, 1, 0]
Output: Final 'arr' = [0, 0, 0, 1, 2, 2, 2, 2]
Explanation: The array is sorted in increasing order.
We can sort the array in one-pass by maintaining three positional pointers ‘zeroPos’, ‘onePos’ and ‘twoPos’ initialised to 0, 0 and N-1, respectively.
Here, ‘zeroPos’ represents the first 1 after all 0s, ‘onePos’ represents the current element, and ‘twoPos’ represents the last unexplored element before all 2s.



Input: Let the binary tree be:

Output: 2
Explanation: The root node is 3, and the leaf nodes are 1 and 2.
There are two nodes visited when traversing from 3 to 1.
There are two nodes visited when traversing from 3 to 2.
Therefore the height of the binary tree is 2.
To find the depth of the tree, We will do the DFS on the tree starting from the root node.
In DFS, we visit all the nodes (child and grandchild nodes) of one child node before going to the second child node, which will help us determine the tree's height. We will take the maximum of both the child’s height.
We will go to the left node and increase one if it is not NULL and do DFS on the left node, the similar thing we will do on the correct node and return the max of the left and right node.
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What is recursion?