SDE - 1

I first converted the number to string. then using two pointer approach I checked if it is palindrome or not.
If it is not palindrome or not I count the even and odd occurrences of numbers to check whether it can be made converted into palindrome.

I did code the problem using smartphone as an example but my code did not run at that time. Here is the running code. Hope it helps-

#include 
#include 
#include 
using namespace std;

//Reusability
class AbstractClass{
virtual void isworthbuy() = 0;
};

//Encapsulation
class smartphone : AbstractClass{
int price;
public:
string brand;
int manf_year;
bool is5g;


void isworthbuy(){
if(is5g){
cout<<"YES"<<'\n';
}
else{
cout<<"NO"<<'\n';
}
}
//Constructor
smartphone(string brand, int manf_year, bool is5g){
this->brand = brand;
this->manf_year = manf_year;
this->is5g = is5g;
}

//Getter
int getprice(){
return price;
}
//Polymorphism
//Setter
void setprice(int number){
if(number < 0){
cout<<"Enter valid price";
return;
}
price = number;
}
void setprice(int number, bool is5g){
if(number < 0){
cout<<"Enter valid price";
return;
}
if(is5g){
price = number + 1000;
}
else{
price = number;
}
}


void print(){
cout }

void print(){
cout< }
};


int main() {
smartphone s1("Apple", 2021, true);
smartphone s2("Samsung", 2021, true);
Apple a1("Apple", 2021, true, "X13");
s1.isworthbuy();
a1.print();
cout<<'\n';
s1.setprice(10000);
s2.setprice(10000, 1);
cout< s1.print();
}