PayU interview experience Real time questions & tips from candidates to crack your interview

SDE - 1

PayU
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2 rounds | 2 Coding problems

Interview preparation journey

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Preparation
Duration: 3 Months
Topics: Data Structures, Algorithms, OOPS, OS, DBMS
Tip
Tip

Tip 1 : Work on Competitive Programming skills. That is one thing most companies look out for during hiring. Solve at least 100 
questions from every topic.
Tip 2 : You should have at least 2 good projects on your resume. Only write the things that you are completely sure of.
Tip 3 : Work on CS fundamentals as well like -OOPS, OS, and DBMS. There will be MCQ questions from this in the coding round as well as in the 1:1 round

Application process
Where: Other
Eligibility: No criteria
Resume Tip
Resume tip

Tip 1 : Need at least 2 good projects on the resume. Write a short 2-3 lines summary of the project and the tech stack 
used.
Tip 2 : Resume should be 1 page only. Try to keep the Resume short with useful information only.
Tip 3 : Your Resume should clearly mention the skillset you have. Companies sometimes filter out Resume based on 
skillset only

Interview rounds

01
Round
Easy
Face to Face
Duration70 Minutes
Interview date20 Mar 2020
Coding problem1

It was on a zoom call from 4PM.

1. Bottom View Of Binary Tree

Moderate
10m average time
90% success
0/80
Asked in companies
OYOMicrosoftAmazon

You are given a 'Binary Tree'.


Return the bottom view of the binary tree.


Note :
1. A node will be in the bottom-view if it is the bottom-most node at its horizontal distance from the root. 

2. The horizontal distance of the root from itself is 0. The horizontal distance of the right child of the root node is 1 and the horizontal distance of the left child of the root node is -1. 

3. The horizontal distance of node 'n' from root = horizontal distance of its parent from root + 1, if node 'n' is the right child of its parent.

4. The horizontal distance of node 'n' from root = horizontal distance of its parent from the root - 1, if node 'n' is the left child of its parent.

5. If more than one node is at the same horizontal distance and is the bottom-most node for that horizontal distance, including the one which is more towards the right.


Example:
Input: Consider the given Binary Tree:

alt text

Output: 4 2 6 3 7

Explanation:
Below is the bottom view of the binary tree.

alt text

1 is the root node, so its horizontal distance = 0.
Since 2 lies to the left of 0, its horizontal distance = 0-1= -1
3 lies to the right of 0, its horizontal distance = 0+1 = 1
Similarly, horizontal distance of 4 = Horizontal distance of 2 - 1= -1-1=-2
Horizontal distance of 5 = Horizontal distance of 2 + 1=  -1+1 = 0
Horizontal distance of 6 = 1-1 =0
Horizontal distance of 7 = 1+1 = 2

The bottom-most node at a horizontal distance of -2 is 4.
The bottom-most node at a horizontal distance of -1 is 2.
The bottom-most node at a horizontal distance of 0 is 5 and 6. However, 6 is more towards the right, so 6 is included.
The bottom-most node at a horizontal distance of 1 is 3.
The bottom-most node at a horizontal distance of 2 is 7.

Hence, the bottom view would be 4 2 6 3 7


Problem approach

It can easily be solved by using the map. Here in the map, we can use keys as node values and values as height of that node. Check while traversing if this is the highest height and keep on adding it to the map. After traversal print the entire map

Try solving now
02
Round
Easy
Face to Face
Duration75 Minutes
Interview date23 Mar 2020
Coding problem1

It was on zoom from 5 PM.

1. Longest Increasing Subsequence

Moderate
0/80
Asked in companies
GrabAmazonSamsung

'N' students are standing in a row. You are given the height of every student standing in the row. Your task is to find the longest strictly increasing subsequence of heights from the row such that the relative order of the students does not change.

A subsequence is a sequence that can be derived from another sequence by deleting zero or more elements without changing the order of the remaining elements.
Problem approach

It can be solved via DP. Take two pointers i and j where i start from 0 indexes and j from i+1. Take an array sum[] initialized with value 1. now check if arr[j] > arr[i] then 
sum[j] = max(sum[j], sum[i] + 1)

now print the max value in sum array

Try solving now

Here's your problem of the day

Solving this problem will increase your chance to get selected in this company

Skill covered: Programming

What is recursion?

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