Angular developer

I applied a two-pointer technique: one pointer was used to iterate through the array, while the other tracked the position to place the next non-zero element. This allowed me to shift all non-zero elements to the front while preserving their order. After that, I filled the remaining positions in the array with zeroes.

I implemented a two-pointer approach where all non-zero elements were shifted to the front while preserving their relative order. After that, the remaining positions in the array were filled with zeroes.

I solved this problem using the two-pointer technique. One pointer was used to track the position for placing non-zero elements, while the other iterated through the array. All non-zero elements were shifted to the front while maintaining their relative order, and once done, the remaining positions in the array were filled with zeroes.