SDE - 1

Given 'N' number of intervals, where each interval contains two integers denoting the boundaries of the interval. The task is to merge all the overlapping intervals and return the list of merged intervals sorted in ascending order.

Two intervals will be considered to be overlapping if the starting integer of one interval is less than or equal to the finishing integer of another interval, and greater than or equal to the starting integer of that interval.

Example:

for the given 5 intervals - [1,4], [3,5], [6,8], [10,12], [8,9].
Since intervals [1,4] and [3,5] overlap with each other, we will merge them into a single interval as [1,5].

Similarly [6,8] and [8,9] overlaps, we merge them into [6,9].

Interval [10,12] does not overlap with any interval.

Final List after merging overlapping intervals: [1,5], [6,9], [10,12]

You have been given a sorted array/list 'arr' consisting of ‘n’ elements. You are also given an integer ‘k’.

Now the array is rotated at some pivot point unknown to you.

For example, if 'arr' = [ 1, 3, 5, 7, 8], then after rotating 'arr' at index 3, the array will be 'arr' = [7, 8, 1, 3, 5].

Now, your task is to find the index at which ‘k’ is present in 'arr'.

Note :

1. If ‘k’ is not present in 'arr', then print -1.
2. There are no duplicate elements present in 'arr'. 
3. 'arr' can be rotated only in the right direction.

Example:

Input: 'arr' = [12, 15, 18, 2, 4] , 'k' = 2

Output: 3

Explanation:
If 'arr' = [12, 15, 18, 2, 4] and 'k' = 2, then the position at which 'k' is present in the array is 3 (0-indexed).

There is a one-dimensional garden of length 'N'. On each of the positions from 0 to 'N', there is a fountain, and this fountain’s water can reach up to a certain range as explained further. In other words, there are 'N' + 1 fountains located at positions 0, 1, 2, 3, …. 'N' which can be activated in the garden.

You are given an integer 'N' and an array/list 'ARR' of length 'N' + 1, where each index of the array denotes the coverage limit of a particular fountain.

A fountain at index 'i' can water the area ranging from the position 'i' - 'ARR'['i'] to 'i' + 'ARR'['i'].

Your task is to find the minimum number of fountains that have to be activated such that the whole garden from position 0 to 'N' has access to the water from at least some fountain.

Note:

1. 0-based indexing is used in the array.
2. We only care about the garden from 0 to 'N' only. So if i - 'ARR'['i'] < 0 or i + 'ARR'['i'] > 'N', you may ignore the exceeding area.
3. If some fountain covers the garden from position 'A' to position 'B', it means that the water from this fountain will spread to the whole line segment with endpoints 'A' and 'B'.

You have been given a directed weighted graph of ‘N’ vertices labeled from 1 to 'N' and ‘M’ edges. Each edge connecting two nodes 'u' and 'v' has a weight 'w' denoting the distance between them.

Your task is to calculate the shortest distance of all vertices from the source vertex 'src'.

Note:

If there is no path between 'src' and 'ith' vertex, the value at 'ith' index in the answer array will be 10^8.

Example :

3 3 1
1 2 2
1 3 2
2 3 -1

In the above graph: 

The length of the shortest path between vertex 1 and vertex 1 is 1->1 and the cost is 0.

The length of the shortest path between vertex 1 and vertex 2 is 1->2 and the cost is 2.

The length of the shortest path between vertex 1 and vertex 3 is 1->2->3 and the cost is 1.

Hence we return [0, 2, 1].

Note :

It's guaranteed that the graph doesn't contain self-loops and multiple edges. Also, the graph does not contain negative weight cycles.

Where do you see yourself in 5 years?

What do you always regret?