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Tip 2: Tailor your resume for each job application, emphasizing relevant skills and experiences that align with the position's specific requirements. This customization enhances your chances of standing out to recruiters and aligning with the role's needs.



Input: 'arr' = [1, 2, 7, -4, 3, 2, -10, 9, 1]
Output: 11
Explanation: The subarray yielding the maximum sum is [1, 2, 7, -4, 3, 2].
The Maximum Subarray Sum problem involves finding the contiguous subarray within a given array of integers that has the largest sum. In other words, given an array of numbers, the task is to determine the subarray with the maximum sum of its elements.



You are given a non-empty binary tree where every node has a positive value. Return the maximum possible path sum between any two leaves of the given tree.



Input:
If the given adjacency matrix is:
[0 1 0]
[1 0 1]
[0 1 0] and 'm' = 3.

Output: YES
Explanation:
The given adjacency matrix tells us that 1 is connected to 2 and 2 is connected to 3. We can use three different colors and color all three nodes.
Hence we return true.
One can see that the number of ways to traverse this tree is a product of factorials of the number of children of each node in an n-ary tree. We can use something like a level order traversal to count the children of a node, then calculate factorials at each node and multiply the factorials calculated at each node.



Given 'N' : 5 (number of packets) and 'M' : 3 (number of students)

And chocolates in each packet is : {8, 11, 7, 15, 2}
All possible way to distribute 5 packets of chocolates among 3 students are -
( 8,15, 7 ) difference of maximum-minimum is ‘15 - 7’ = ‘8’
( 8, 15, 2 ) difference of maximum-minimum is ‘15 - 2’ = ‘13’
( 8, 15, 11 ) difference of maximum-minimum is ‘15 - 8’ = ‘7’
( 8, 7, 2 ) difference of maximum-minimum is ‘8 - 2’ = ‘6’
( 8, 7, 11 ) difference of maximum-minimum is ‘11 - 7’ = ‘4’
( 8, 2, 11 ) difference of maximum-minimum is ‘11 - 2’ = ‘9’
( 15, 7, 2 ) difference of maximum-minimum is ‘15 - 2’ = 13’
( 15, 7, 11 ) difference of maximum-minimum is ‘15 - 7’ = ‘8’
( 15, 2, 11 ) difference of maximum-minimum is ‘15 - 2’ = ‘13’
( 7, 2, 11 ) difference of maximum-minimum is ‘11 - 2’ = ‘9’
Hence there are 10 possible ways to distribute ‘5’ packets of chocolate among the ‘3’ students and difference of combination (8, 7, 11) is ‘maximum - minimum’ = ‘11 - 7’ = ‘4’ is minimum in all of the above.
Given an array/list of integer numbers 'CHOCOLATES' of size 'N', where each value of the array/list represents the number of chocolates in the packet. There are an ‘M’ number of students and the task is to distribute the chocolate to their students. Distribute chocolate in such a way that:
1. Each student gets at least one packet of chocolate.
2. The difference between the maximum number of chocolate in a packet and the minimum number of chocolate in a packet given to the students is minimal.



Case1: Every single character is a palindrome of length 1
L(i, i) = 1 (for all indexes i in the given sequence)
Case2: If the first and last characters are not the same
If (X[i] != X[j]) L(i, j) = max{L(i + 1, j), L(i, j – 1)}
Case3: If there are only 2 characters and both are the same
Else if (j == i + 1) L(i, j) = 2
Case4: If there are more than two characters, and the first and last characters are the same
Else L(i, j) = L(i + 1, j – 1) + 2
We can improve the time complexity using DP

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