SDE - 1

Given an array/list of integers of length ‘N’, there is a sliding window of size ‘K’ which moves from the beginning of the array, to the very end. You can only see the ‘K’ numbers in a particular window at a time. For each of the 'N'-'K'+1 different windows thus formed, you are supposed to return the maximum element in each of them, from the given array/list.

You are given an array “arr'' of integers. Your task is to find the contiguous subarray within the array which has the largest product of its elements. You have to report this maximum product.

An array c is a subarray of array d if c can be obtained from d by deletion of several elements from the beginning and several elements from the end.

For e.g.- The non-empty subarrays of an array [1,2,3] will be- [1],[2],[3],[1,2],[2,3],[1,2,3]. 

For Example:

If arr = {-3,4,5}.
All the possible non-empty contiguous subarrays of “arr” are {-3}, {4}, {5}, {-3,4}, {4,5} and {-3,4,5}.
The product of these subarrays are -3, 4, 5, -12, 20 and -60 respectively.
The maximum product is 20. Hence, the answer is 20.

Follow Up:

Can you solve this in linear time and constant space complexity?

You will be given a stream of numbers, and you need to find the 'kth' largest number in the stream at any given time.

As the stream of numbers can not be given during compile time, so you need to design a data structure which can accept infinite numbers and can return the 'kth' largest number at any given time.

The stream of numbers is nothing but a large collection of numbers from which integers are read at runtime, such as the user will never know the upper limit on the number of integers that will be read.

The implemented data structure must support the following operations:

1. add(DATA) :
   This function should take one argument of type and store it in its pool and returns the 'kth' largest number from the current pool of integers.

You will be given 'q' queries:

val - For this query, insert the integer into your current pool of integers and return the 'kth' largest integer from the existing pool of integers.

Note

 1. The maximum number of integers that will be given will always be under memory limits.

 2. You will also be given an initial pool of integers whose size equals k.

 3. The maximum number of queries will be less than 10^5.

 4. The 'kth' largest element is not the 'kth' distinct element but the 'kth' largest element in the sorted order.

 5. There will be at least one query of type 2.

You have been given a binary tree of integers with N number of nodes. Your task is to check if that input tree is a BST (Binary Search Tree) or not.

A binary search tree (BST) is a binary tree data structure which has the following properties.

• The left subtree of a node contains only nodes with data less than the node’s data.
• The right subtree of a node contains only nodes with data greater than the node’s data.
• Both the left and right subtrees must also be binary search trees.

Example :

Answer :

Level 1: 

All the nodes in the left subtree of 4 (2, 1, 3) are smaller 
than 4, all the nodes in the right subtree of the 4 (5) are 
larger than 4.

Level 2 :

For node 2:
All the nodes in the left subtree of 2 (1) are smaller than 
2, all the nodes in the right subtree of the 2 (3) are larger than 2.
For node 5:
The left and right subtrees for node 5 are empty.

Level 3:

For node 1:
The left and right subtrees for node 1 are empty.
For node 3:
The left and right subtrees for node 3 are empty.

Because all the nodes follow the property of a binary search tree, the above tree is a binary search tree.

You are given an integer grid of size ‘N’x’M’, and the cell of the grid contains either of the three values:

0 - An empty cell.

1 - A fresh orange.

2 - A rotten orange.

Every minute, any fresh orange adjacent(4-directionally) to a rotten orange becomes rotten.

You must return the minimum time after which no fresh oranges are left. Return -1 if it's impossible to rot all the fresh oranges.

Example:

Input: [[2,1,1],[1,1,0],[0,0,0]]

Output: 2

At T=0, only orange at (0,0) is rotten.
At T=1, oranges at (0,0),(0,1) and (1,0) are rotten.
At T=2, oranges at (0,0),(0,1),(1,0),(0,2) and (1,1) are rotten. 
No fresh oranges are left after T=2.

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