SDE - 1

You are given an array 'arr' of length 'n'. Find the index(0-based) of a peak element in the array. If there are multiple peak numbers, return the index of any peak number.

Peak element is defined as that element that is greater than both of its neighbors. If 'arr[i]' is the peak element, 'arr[i - 1]' < 'arr[i]' and 'arr[i + 1]' < 'arr[i]'.

Assume 'arr[-1]' and 'arr[n]' as negative infinity.

Note:

1.  There are no 2 adjacent elements having same value (as mentioned in the constraints).
2.  Do not print anything, just return the index of the peak element (0 - indexed).
3. 'True'/'False' will be printed depending on whether your answer is correct or not.

Example:

Input: 'arr' = [1, 8, 1, 5, 3]

Output: 3

Explanation: There are two possible answers. Both 8 and 5 are peak elements, so the correct answers are their positions, 1 and 3.

Given an array of non-negative integers ‘ARR’ of length ‘N’, you are initially positioned at the array's first index.

Each element in the array represents your maximum jump length at that position.

Return the minimum number of jumps required to reach the last index.

If it is not possible to reach the last index, return -1.

Example:

Input:

‘N’ = 3
‘ARR’ = [ 2, 1, 1 ]

The shortest way to reach index 2 is
Index 0 => Index 2
that requires only 1 jump.

You have been given a sorted array/list 'arr' consisting of ‘n’ elements. You are also given an integer ‘k’.

Now the array is rotated at some pivot point unknown to you.

For example, if 'arr' = [ 1, 3, 5, 7, 8], then after rotating 'arr' at index 3, the array will be 'arr' = [7, 8, 1, 3, 5].

Now, your task is to find the index at which ‘k’ is present in 'arr'.

Note :

1. If ‘k’ is not present in 'arr', then print -1.
2. There are no duplicate elements present in 'arr'. 
3. 'arr' can be rotated only in the right direction.

Example:

Input: 'arr' = [12, 15, 18, 2, 4] , 'k' = 2

Output: 3

Explanation:
If 'arr' = [12, 15, 18, 2, 4] and 'k' = 2, then the position at which 'k' is present in the array is 3 (0-indexed).

Two taps A and B can fill a cistern in 48 minutes and 64 minutes respectively. Tap C can empty the tank in 96 minutes. If all the taps are opened together, in how much time the cistern will get filled?

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