SDE - 1

Given two sorted arrays 'a' and 'b' of size 'n' and 'm' respectively.

Find the median of the two sorted arrays.

Median is defined as the middle value of a sorted list of numbers. In case the length of list is even, median is the average of the two middle elements.

The expected time complexity is O(min(logn, logm)), where 'n' and 'm' are the sizes of arrays 'a' and 'b', respectively, and the expected space complexity is O(1).

Example:

Input: 'a' = [2, 4, 6] and 'b' = [1, 3, 5]

Output: 3.5

Explanation: The array after merging 'a' and 'b' will be { 1, 2, 3, 4, 5, 6 }. Here two medians are 3 and 4. So the median will be the average of 3 and 4, which is 3.5.

Measure a time of 45 minutes by burning two ropes each of which takes 1 hour to burn out.

The ropes are of same length but none of the two burns at a uniform rate throughout the length. That's why you cannot just measure a point at three-fourth of the length of a rope and start burning at that point to measure 45 minutes.

Only saving grace is the allowance that one or both of the ropes can be burned simultaneously at multiple points.

You are given an array/list ARR consisting of N integers. Your task is to find all the distinct triplets present in the array which adds up to a given number K.

An array is said to have a triplet {ARR[i], ARR[j], ARR[k]} with sum = 'K' if there exists three indices i, j and k such that i!=j, j!=k and i!=j and ARR[i] + ARR[j] + ARR[k] = 'K'.

Note:

1. You can return the list of values in any order. For example, if a valid triplet is {1, 2, -3}, then {2, -3, 1}, {-3, 2, 1} etc is also valid triplet. Also, the ordering of different triplets can be random i.e if there are more than one valid triplets, you can return them in any order.
2. The elements in the array need not be distinct.
3. If no such triplet is present in the array, then return an empty list, and the output printed for such a test case will be "-1".