SDE - 2

use the LinkedHashSet (Set Interface) to retain the original insertion order of the elements into the set.

The main factor that we must keep in mind when dealing with arrays is not the elements that have duplicates. The main problem here is removing the duplicates instead. Arrays are static data structures that are of fixed length, thus not possible to be altered. So, to delete elements from arrays, you need to create new arrays and duplicate the content into these new arrays.

First, you must convert the arrays into Arraylists and then create LinkedHashSets from these ArrayLists. If input arrays contain a larger number of duplicates then it can result in multiple temporary arrays, thus increasing the cost of importing the content. This restriction enforces that we approach this problem in a manner that requires less memory and processing power.

We must remove the duplicates but not copy them into the resulting arrays, thus not deleting the duplicates entirely but simply replacing them with 0 as the default value.

Declare a string.
Take out the length of that string.
Loop through the characters of the string.
Add the characters in reverse order in the new string.
String str = "hello";

String reverse = "";

int length = str.length();

for (int i = 0; i < length; i++) {

reverse = str.charAt(i) + reverse;

}

System.out.println(reverse);

Tip 1 : Be confidence about introduction part do not get hesitated during your HR discussion
Tip 2 : Try to be uniform the way & show them interested to join the organization.
Tip 3 : Majorly the focus on behavioural and communication skills.