Tip 1 : Must do Previously asked Interview as well as Online Test Questions.
Tip 2 : Go through all the previous interview experiences from Codestudio and Leetcode.
Tip 3 : Do at-least 2 good projects and you must know every bit of them.
Tip 1 : Have at-least 2 good projects explained in short with all important points covered.
Tip 2 : Every skill must be mentioned.
Tip 3 : Focus on skills, projects and experiences more.
Technical round based on DSA.



The given linked list is 1 -> 2 -> 3 -> 4-> NULL. Then the reverse linked list is 4 -> 3 -> 2 -> 1 -> NULL and the head of the reversed linked list will be 4.
Can you solve this problem in O(N) time and O(1) space complexity?
One way is to use recursion to reverse the list. Divide the linked list in two halves, the first node and the rest of the list. Reverse the second half using recursion and append the first half, that is the first node at the end of the reversed linked list. Return the head of the reversed linked list.



Input: 'arr' = [1, 2, 7, -4, 3, 2, -10, 9, 1]
Output: 11
Explanation: The subarray yielding the maximum sum is [1, 2, 7, -4, 3, 2].
Divide the array into 2 halves.
Get the answer of left and right parts of the array by recursion.
Get the answer of Maximum subarray sum such that the subarray crosses the midpoint.
To find the maximum subarray sum of crossing points we need to find the maximum sum starting from mid point and ending at some point on the left of mid, then find the maximum sum starting from mid + 1 and ending with some point on right of mid + 1. Total sum would be the sum of both left part and right part.
Maximum of all three sums would be the final answer.
Technical interview round with questions on OOPs concepts mainly.
Difference between C and C++
Java questions on multi threading, exception handling.
Distinguish between stack and queue.

Here's your problem of the day
Solving this problem will increase your chance to get selected in this company
What is recursion?