Tip 1 : Give regular programming contests. Try to achieve Codeforce Candidate Master level or equivalent
Tip 2 : Learn/Practice DSA.
Tip 3 : Do at least 2 projects on your resume, on topics such as ML, NLP, Dev etc
Tip 1 : Mention atleast 2 good projects and be thorough with them.
Tip 2 : Mention CP contest rankings or ratings
The round name was PCCAT - Proctored Criteria Cognitive Aptitude Test. It was a 15 minutes round with 50 questions.
Questions were based on aptitude testing in the section of Mathematics, Reasoning and Vocabulary.
The difficulty level of questions - Easy
The difficulty level of the round - Hard. As 15 minutes is very less time to go through all 50 questions and the cutoff is set to 45, making it a near-impossible task.
This round was basically a brief discussion of resumes. We discussed all the projects I mentioned in my resume and tech stack used to complete the project.
Two DSA problems of difficulty rating of 1500-1800 on Codeforces.



An integer 'a' is closer to 'X' than an integer 'b' if:
|a - X| < |b - X| or ( |a - X| == |b - X| and a < b )
if X = 4, 3 is closer to 'X' than 9, as |3-4| < |9-4| i.e., 1 < 5 and if X = 4, 2 and 6 are equally close to it, as |2-4| == |6-4| = 2, but we say 2 is closer to 4 than 6, as 2 is smaller.
I proposed the following solution -
Perform a binary search on distance. In each iteration of the binary search, check how many pairs have a distance less than mid and then update low and high bounds in accordance with K.


A point on the circumference of a circle is considered an inner point.
Let y be the smallest integer such that 2^y >= N.
So, we will call G(y) till we get a number in the desired range.
Follow-up - Expected Number of calls to G before we get a number in the desired range.
This round was majorly based on my resume discussion. It was with a senior VP. We had an in-depth discussion on my past interview experiences, my projects etc.
What are your expectations?
Who is your role model?

Here's your problem of the day
Solving this problem will increase your chance to get selected in this company
What is recursion?