Project Engineer

You are given a positive integer N and an equation 1/X + 1/Y = 1/N

You need to determine the count of all possible positive integral solutions (X, Y) for the above equation.

Note:

1. X and Y should be greater than 0.
2. (X, Y) and (Y, X) are considered different solutions if X is not equal to Y, i.e. (X, Y) and (Y, X) will not be distinct if X=Y.

You are provided with a list of numbers from ‘0’ to (2 * ’N’ - 1). You have to find the minimum number of swaps needed to make every even number ‘E’ (present in the list) adjacent to (‘E’ + 1).

For Example:

List = [3, 0, 2, 1]

We have to make ‘0’ adjacent to ‘1’ and ‘2’ to ‘3’. And, to achieve this we can swap ‘0’ with ‘2’.

New list = [3, 2, 0, 1].

Therefore, the answer (minimum number of swaps) is equal to 1.

Note:

There will be only distinct numbers present in the given list.

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