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X = 11
The sum of nodes 7, 3, 1 is 11. So we will return True.
Step 1 : Implemented brute force solution first.
Step 2 : Then saw as order of elements does not mattered so thought of sorting it and to use 2 pointer
Step 3 : Implemented it.



For the given binary tree:

The Inorder traversal will be [5, 3, 2, 1, 7, 4, 6].




Step1 : First I provided the solution , that just do the inorder traversal and check whether the output is sorted or not
Step2 : Interviewer asked to do without inorder traversal. So implemented with recursion too



Here, sorted paths mean that the expected output should be in alphabetical order.
Given a square matrix of size 4*4 (i.e. here 'N' = 4):
1 0 0 0
1 1 0 0
1 1 0 0
0 1 1 1
Expected Output:
DDRDRR DRDDRR
i.e. Path-1: DDRDRR and Path-2: DRDDRR
The rat can reach the destination at (3, 3) from (0, 0) by two paths, i.e. DRDDRR and DDRDRR when printed in sorted order, we get DDRDRR DRDDRR.
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What is recursion?