Problem of the day
Given an integer N, count and return the number of zeros that are present in the given integer using recursion.
Integer N
Output Format :
Number of zeros in N
0 <= N <= 10^9
0
1
00010204
2
Even though "00010204" has 5 zeros, the output would still be 2 because when you convert it to an integer, it becomes 10204.
708000
4