


You have been given a circular path. There are N petrol pumps on this path that are numbered from 0 to N - 1 (Both inclusive). Each petrol pump has two values associated with it:
1)The amount of petrol that is available at this particular petrol pump.
2)The distance to reach the next petrol pump.
You are on a truck having an empty tank of infinite capacity. You can start the tour from any of the petrol pumps. Your task is to calculate the first petrol pump from where the truck will be able to complete the full circle or determine if it is impossible to do so.
You may assume that the truck will stop at every petrol pump and it will add the petrol from that pump to its tank. The truck will move one kilometre for each litre of petrol consumed.
The first line of input contains an integer 'N' representing the number of petrol pumps.
Each of the next N lines will contain a pair of space-separated integers representing the amount of petrol that pump has and the distance to reach the next petrol pump, respectively.
Output Format :
Print an integer representing the index of the first petrol pump from which we should start the tour. If no such petrol pump exists, print ‘-1’.
Note:
You do not need to print anything; it has already been taken care of. Just implement the given function. Make sure that the output has 0 - based indexing.
1 <= N <= 5*10^5
1 <= Amount of petrol on each pump <= 10^9
1 <= Distance to next pump <= 10^9
Where N is the total number of petrol pumps on the circular path.
Time Limit: 1sec
3
1 5
10 3
3 4
1
If we start from the petrol pump at index 0, we will not be able to travel to index one as petrol available for travelling is less than the distance.
If we start at index 1, we can complete our journey (1 -> 2 -> 0 -> 1) easily.
3
1 10
10 20
3 10
-1
We will not be able to visit every petrol pump from any index.
Try every possible petrol pump as the starting pump.
O(N^2), where N denotes the total number of petrol stations.
As every petrol pump will be visited at most N times (for each of the N starting points), the time complexity will be O(N^2).
O(1), constant space is used.