


Given two singly linked lists, 'FIRST_HEAD' and 'SECOND_HEAD'. Your task is to find the 'MERGING POINT' i.e. the data of the node at which merging starts. If there is no merging, return -1.
For example:-
The given Linked Lists are merging at node c1.
In this case, c1 is 'MERGING POINT'.

The input format contains three lines consisting of three singly-linked lists.
All three lines contain the elements of the singly linked list separated by a single space and terminated by -1.
So first linked list would contain
a1, a2, ...an, c1, -1.
Similarly, the second line would contain
b1,b2, ...bm, c1, -1.
The third line would contain
c2, c3, ....ck, -1.
Refer 'a1, a2, ......, b1, b2, ......, c1, c2, ....., ck' from this image.

The only line of output contains data of the first merged node's data.
<b>If there is no merging output should contain -1. </b>
You don't have to explicitly print by yourself. It has been taken care of.
0 <= N <= 10^5
0 <= M <= 10^5
0 <= K <= 10^5.
-10^9 <= data <= 10^9 and data != -1
Time Limit: 1 sec
4 1 8 -1
5 6 1 8 -1
4 5 -1
8
As shown in the diagram the node with data is 8 at which merging starts

1 2 3 4 5 -1
2 3 4 5 -1
6 7 -1
5
2 6 4 -1
1 5 -1
-1
-1