


You are given an infinite array consisting of only ones and zeroes, in sorted order. You have to find the index of the first occurrence of 1.
Example:If the array is 0 0 0 0 1 1 1 1… then, the first occurrence of 1 will be at index 4 therefore the answer here is 4.
Note:
As the array size is infinite, the actual array won’t be given to you. Instead, you will be able to access the array elements by calling a method named ‘get’.
get(i) : returns the value present at index I.
Indexing is 0-based.
Instead of representing an infinite array in the input, we give the index of the first occurrence of 1 in the input itself. However, this input will be completely hidden from the user.
It is guaranteed that the answer will fit in a 64-bit integer.
The only input line contains an integer X, the index of the first occurrence of 1. (Hidden to the user)
Output Format:
Print an integer denoting the index of the first occurrence of 1.
Note:
You do not need to print anything, the output has already been taken care of. Just implement the given function.
0 <= ARR[i] <= 1
Time limit: 1sec
10
10
1
1
Go for a linear search.
The simplest approach would be to start from the beginning, i.e. index 0, and check if there’s a 1 at this index. If yes, then we have found the first occurrence of 1. Else, we check for the next index.
O(X), where X is the index of the first occurrence of 1.
We search X indices before arriving at index X, and checking at each index takes O(1) time.
O(1), as no extra space is required.