# Aptitude for Placement: TCS, Infosys Aptitude Questions for Placement [With Answers]

Are you a graduate or fresher looking for a job in India? If so, you’ll need to prepare for the aptitude test that is often a part of the hiring process. Your primary skills and understanding are assessed on aptitude exams in areas like logical thinking, verbal reasoning, and mathematical reasoning. They might be difficult, but with the right preparation, you can succeed.

This article emphasizes Firstnaukri’s FNAT as the top portal for taking the aptitude exam. It seeks to instruct ambitious job seekers in India on successfully preparing for aptitude questions.

## What is an Aptitude Test?

An aptitude test is a standardized evaluation that determines a person’s capacity to learn or use a certain skill. In contrast to an intelligence test, which gauges a person’s present cognitive ability, it does not assess intelligence. A lot of employment selections and educational and career counseling include the use of aptitude tests.

Aptitude tests come in various forms, each of which is intended to evaluate a particular talent or group of skills. These include:

**Numerical reasoning:**Questions in this section are based on statistics, charts, graphs, and figures.**Verbal reasoning:**Questions in this section test your ability to comprehend and reason complex concepts expressed in simple English**Diagrammatic tests:**In these questions, you will be asked to analyze a sequence of inductive shapes, abstract patterns, and sometimes numbers**Situational judgment tests:**These questions basically assess how you approach situations that you may encounter in a workplace.**Inductive reasoning:**These questions are based on derivations of general principles from certain observations.**Cognitive ability:**It is basically the use of mental activities and skills to do reasoning, understand situations, remember a sequence of activities, and pay enough attention to solve the puzzle.**Mechanical reasoning tests:**These puzzles are part of the test technical and engineering positions.**In-tray exercises:**Questions in this section are business-related scenarios that can assess how to prioritize tasks.

## How to Prepare for Aptitude Tests for Placements?

Preparation for aptitude questions is essential for graduates and freshers looking for job placements in India. You may improve your aptitude abilities and increase your chances of success using a systematic strategy, routine practice, and Firstnaukri’s FNAT materials.

The following advice will help you get ready for aptitude exams for job placements in India:

- Know the different categories of aptitude questions. It’s crucial to comprehend the numerous varieties of aptitude questions. Quantitative reasoning problems, verbal reasoning problems, and logical reasoning problems are some of the most typical forms.
- Practicing is essential. Practicing as much as you can before taking an aptitude exam is the best approach to becoming ready.
- Identify your vulnerabilities. Consider your strengths and shortcomings after you’ve practiced answering various aptitude questions.
- Time management is essential. It’s crucial to use your time carefully. You should practice answering questions in a timed environment to become accustomed to the strain.
- Be concentrated and calm. It’s simple to become anxious during an aptitude exam, but it’s crucial to maintain your composure and concentration

If you follow these tips, you’ll be well on your way to acing your aptitude test and landing your dream job.

## TCS Aptitude Questions for Fresher’s Placement [Updated]

The pattern of the TCS Aptitude Questions and Answers has recently been modified, and the test has been divided into two main sections, the TCS Foundation and the TCS Advanced Test. The TCS Foundation Test is quite challenging, whereas the TCS Advanced Aptitude is very difficult.

### TCS Foundation Level Questions

**Question 1: **If 3x – 7 = 5, what is the value of x?

Given, 3x – 7 = 5

Adding 7 to both sides: 3x = 12

Dividing both sides by 3: x = 4

Therefore, the value of x is 4.

**Question 2: **If a shopkeeper sells a shirt for ₹240 at a 20% discount on the marked price, what is the marked price?

Let the marked price be x.

Discount = 20% of x = 0.20x

Selling price = Marked price – Discount = x – 0.20x = 0.80x

Given that selling price = ₹240

So,

0.80x = ₹240

Dividing both sides by 0.80: x = ₹300

Therefore, the marked price of the shirt is ₹300.

**Question 3: **If a train travels at a speed of 72 km/h, how many kilometers will it travel in 3 hours?

Distance = Speed × Time

Distance = 72 km/h × 3 hours = 216 km

The train will travel 216 kilometers in 3 hours.

**Question 4: **Simplify: (4² + 3³) / 5

(4² + 3³) / 5 = (16 + 27) / 5 = 43 / 5 = 8.6

**Question 5: **A bag contains 5 red balls and 3 green balls. What is the probability of drawing a red ball?

Total number of balls = 5 (red) + 3 (green) = 8

Probability of drawing a red ball = Number of red balls / Total number of balls

= 5 / 8

### TCS Advance Level Aptitude Questions

**Question 6: **The sum of two consecutive odd numbers is 44. What are the numbers?

Let the first odd number be x.

The next consecutive odd number = x + 2 (since odd numbers are spaced by 2).

Given that their sum is 44:

x + (x + 2) = 44

2x + 2 = 44

Subtracting 2 from both sides: 2x = 42

Dividing by 2: x = 21

So, the first odd number = 21, and the next odd number = 23.

**Question 7: **A rectangular field is 40 meters long and 30 meters wide. If a path of uniform width is constructed around the field that doubles the total area, what is the width of the path?

Original area = Length × Width

= 40 m × 30 m

= 1200 sq. m

Let the width of the path be ‘x’.

New length = 40 m + 2x and new width = 30 m + 2x

New area = (New length) × (New width) = (40 + 2x) × (30 + 2x)

Given that the new area is twice the original area:

2 × Original area = New area

2 × 1200 = (40 + 2x) × (30 + 2x)

2400 = 1200 + 40x + 60x + 4x²

4x² + 100x – 1200 = 0

Dividing by 4: x² + 25x – 300 = 0

Factoring: (x + 30)(x – 5) = 0

So, the width of the path (x) can be either -30 (not possible) or 5 meters.

**Question 8: **The average of 5 consecutive even numbers is 36. What is the largest number?

Let the first even number be x.

The next consecutive even numbers = x + 2, x + 4, x + 6, x + 8.

Given that their average is 36:

(x + x + 2 + x + 4 + x + 6 + x + 8) / 5 = 36

5x + 20 = 180

5x = 160

x = 32

The largest number = x + 8 = 32 + 8 = 40.

**Question 9: **If log₃(x) = 4, what is the value of x?

Using the property of logarithms:

logₐ(b) = c is equivalent to b = a^c

So, x = 3^4 = 3 × 3 × 3 × 3 = 81.

**Question 10: **A car rental agency charges a base rate of ₹30 per day and an additional ₹0.20 per mile driven. If a customer is charged ₹56 for renting the car, how many miles did they drive?

Let the number of miles driven be ‘m’.

Total cost = Base rate + (Additional cost per mile × Number of miles)

₹56 = ₹30 + (₹0.20 × m)

₹56 – ₹30 = ₹0.20m

₹26 = ₹0.20m

Dividing by ₹0.20: m = 130 miles.

The customer drove 130 miles.

## Infosys Aptitude Questions and Answers

Solve these Infosys Aptitude Questions for your placements. These questions are specifically designed to help you get through the freshers placement tests.

**Question 1: **A number when multiplied by 5 and then divided by 7 gives a quotient of 25. What is the number?

Let the number be ‘x’.

According to the given information, (5x) / 7 = 25

Multiplying both sides by 7: 5x = 175

Dividing both sides by 5: x = 35

So, the number is 35.

**Question 2: **If the average of five numbers is 32 and the sum of the first three numbers is 105, what is the sum of the last two numbers?

Let the five numbers be a, b, c, d, and e.

Given, (a + b + c + d + e) / 5 = 32

Multiplying both sides by 5: a + b + c + d + e = 160

Also, a + b + c = 105

Substituting the value of a + b + c into the first equation:

105 + d + e = 160

d + e = 160 – 105

d + e = 55

The sum of the last two numbers is 55.

**Question 3: **The perimeter of a rectangle is 40 meters, and the length is 12 meters. What is the width of the rectangle?

Perimeter of a rectangle = 2 × (Length + Width)

Given, 40 = 2 × (12 + Width)

Dividing both sides by 2: 20 = 12 + Width

Subtracting 12 from both sides: Width = 20 – 12 = 8 meters

The width of the rectangle is 8 meters.

**Question 4: **If 2x – 5 = 11, what is the value of x?

Given, 2x – 5 = 11

Adding 5 to both sides: 2x = 16

Dividing both sides by 2: x = 8

So, the value of x is 8.

**Question 5: **If a number is increased by 15% and the result is 138, what is the original number?

Let the original number be ‘x’.

Given, (x + 0.15x) = 138

Combining terms: 1.15x = 138

Dividing both sides by 1.15: x = 120

The original number is 120.

**Question 6: **The sum of three consecutive odd integers is 183. What are the integers?

Let the first odd integer be x.

The next consecutive odd integers are x + 2 and x + 4.

Given, x + (x + 2) + (x + 4) = 183

Simplifying: 3x + 6 = 183

Subtracting 6 from both sides: 3x = 177

Dividing both sides by 3: x = 59

So, the three consecutive odd integers are 59, 61, and 63.

**Question 7: **The ages of three friends are in the ratio 4:5:6. If the sum of their ages is 75, what is the age of the youngest friend?

Let the ages be 4x, 5x, and 6x.

Given, 4x + 5x + 6x = 75

Simplifying: 15x = 75

Dividing both sides by 15: x = 5

The age of the youngest friend = 4x = 4 × 5 = 20 years.

**Question 8: **If log₂(x) + log₂(y) = 6 and log₂(x) – log₂(y) = 2, what is the value of x/y?

Using logarithmic properties: log₂(x) + log₂(y) = log₂(xy)

Given, log₂(xy) = 6

Similarly, log₂(x) – log₂(y) = log₂(x/y)

Given, log₂(x/y) = 2

So, we have:

log₂(xy) = 6

log₂(x/y) = 2

Using logarithmic properties: log₂(xy) – log₂(x/y) = log₂((xy) / (x/y))

6 – 2 = log₂((xy) / (x/y))

4 = log₂((xy²) / x)

4 = log₂(y²)

Converting to exponential form: 2^4 = y²

16 = y²

Therefore, y = √16 = 4

Substituting the value of y into the first equation: log₂(x) + log₂(4) = 6

log₂(4x) = 6

4x = 2^6

4x = 64

x = 16

So, x/y = 16/4 = 4.

**Question 9: **A car travels a distance of 240 km at a certain speed. If the speed is increased by 20 km/h, the same distance is covered in 3 hours less. Find the original speed of the car.

Let the original speed of the car be ‘x’ km/h.

Given, Distance = Speed × Time

Original time taken to cover 240 km = 240 / x hours

When the speed is increased by 20 km/h, the new speed = (x + 20) km/h

Time taken to cover 240 km at the increased speed = 240 / (x + 20) hours

According to the given information:

240 / x – 240 / (x + 20) = 3

To solve this equation, let’s find a common denominator:

[(240 × (x + 20)) – (240 × x)] / (x × (x + 20)) = 3

Simplifying:

240x + 4800 – 240x = 3x² + 60x

4800 = 3x² + 60x

3x² + 60x – 4800 = 0

Dividing the equation by 3:

x² + 20x – 1600 = 0

Factoring the quadratic equation:

(x + 40)(x – 40) = 0

So,

x = -40 or x = 40

Since speed cannot be negative, the original speed of the car is 40 km/h.

**Question 10: **In a two-digit number, the tens digit is 3 more than the unit digit. When the number is divided by the sum of its digits, the quotient is 7 and the remainder is 4. What is the number?

Let the tens digit be ‘x’ and the unit digit be ‘y’. The two-digit number is then 10x + y.

Given, x = y + 3

Also, (10x + y) / (x + y) = 7 with a remainder of 4.

Rewriting the division equation:

10x + y = 7(x + y) + 4

10x + y = 7x + 7y + 4

Substituting the value of x from the first equation:

7(y + 3) + y = 10x + y

7y + 21 + y = 10y + y

8y + 21 = 11y

21 = 3y

y = 7

Substituting the value of y back into the first equation:

x = y + 3

x = 7 + 3

x = 10

So, the tens digit is 10, and the unit digit is 7.

The two-digit number is 10x + y = 10(10) + 7 = 107.

## Why do Aptitude Questions Matter?

Aptitude tests throughout the hiring process are essential because they allow companies to assess a candidate’s fit for a certain position. These kinds of questions are intended to evaluate a candidate’s aptitude for maths, verbal reasoning, logic, data interpretation, and analytical thinking. Your chances of receiving a desirable job offer might be greatly increased by performing well on aptitude tests.

The Firstnaukri FNAT is a thorough aptitude exam that is based on real aptitude test questions asked by companies over the previous five years. The exam includes all of the main aptitude domains, such as logical thinking, verbal reasoning, and mathematical reasoning. It is an ideal method for preparing for India’s placement-related aptitude exams. Additionally, the questions are based on the most recent developments in aptitude testing, ensuring you are ready for everything that may be tossed at you.

**Check:**

- 65 Logical Reasoning Questions and Answers for Freshers
- Aptitude Test Sample Questions & Answers
- All You Need to Know About Online Aptitude Tests

## FAQs on Aptitude Test for Placement

### What is an aptitude test for job preparation?

A job candidate’s cognitive skills, work practices, or personality qualities can be assessed with an aptitude test. The purpose of aptitude tests is to gauge how effectively you can reason, solve problems, and work with numbers and logic. They are a tested technique for evaluating employability abilities.

- How to Prepare for An Aptitude Test During Campus Placements
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- Assessment Tests: How to Crack This Crucial Stage of the Recruitment Process

### What are the key topics to focus on while preparing for aptitude questions?

Key topics to focus on while preparing for aptitude questions include quantitative aptitude, logical reasoning, verbal ability, data interpretation, and analytical thinking.

### How to prepare for an aptitude test in 2 days for placement?

To prepare for an aptitude test in 2 days for college placement, keep in mind the following pointers:

- Attempt practice papers and mock exams.
- Concentrate on grasping the concepts well.
- Have effective time management.
- Eat a nutritious dinner, and have a restful night’s sleep.
- Stay optimistic.

### How to pass the college placement aptitude test?

Remember to constantly practice aptitude questions by completing mock sample questions and questions from past exams if you want to pass the college placement aptitude test. To acquire a better understanding of recruiting, study the interview experiences of candidates from prior years.

- What is your Biggest Achievement: Sample Responses for Freshers
- Highlighting Technical Skills as a Fresher on Your Resume

### Why should I choose Firstnaukri’s FNAT for aptitude test preparation?

FNAT provides a realistic testing experience with genuine aptitude questions asked by companies, a comprehensive question bank, performance analysis, and trusted recognition among recruiters.