
In this tree, cities 5 and 6 are directly below the capital city; hence, the answer is 5, 6.
The first line contains a single integer ‘T’ denoting the number of test cases to be run. Then the test cases follow.
The first line of each test case contains the elements of the binary tree in the level order form separated by a single space.
If any node does not have a left or right child, take -1 in its place. Refer to the example below.
1
2 3
-1 4 -1 -1
5 -1
-1 -1
Explanation :
Level 1 :
The root node of the tree is 1
Level 2 :
Left child of 1 = 2
Right child of 1 = 3
Level 3 :
Left child of 2 = null (-1)
Right child of 2 = 4
Left child of 3 = null (-1)
Right child of 3 = null (-1)
Level 4 :
Left child of 4 = 5
Right child of 4 = null (-1)
Level 5 :
Left child of 5 = null (-1)
Right child of 5 = null (-1)
The first not-null node (of the previous level) is treated as the parent of the first two nodes of the current level. The second not-null node (of the previous level) is treated as the parent node for the next two nodes of the current level and so on.
The input ends when all nodes at the last level are null (-1).
Note: The above format was just to provide clarity on how the input is formed for a given tree.
The sequence will be put together in a single line separated by a single space. Hence, for the above-depicted tree, the input will be given as:
1 2 3 -1 4 -1 -1 5 -1 -1 -1
For each test case, return a List containing all the cities vertically below the root node.
Output for each test case will be printed in a separate line.
You are not required to print anything; it has already been taken care of. Just implement the function and return the answer.
1 <= T <= 100
1 <= N <= 3000
0 <= NodeVal <= 10^9
Time Limit: 1sec
So the approach is we have to traverse through the tree, from both left and right sides, until we reach the leaf node and keep a variable ‘Distance’ which will calculate how far is the current node from the root node, if ‘Distance’ is zero we push that node into list ‘Ans’.
The steps are as follows: