


Input: ‘n’ = 5
Output: 0 1 1 2 3
Explanation: First 5 Fibonacci numbers are: 0, 1, 1, 2, and 3.
You don't need to print anything. Just implement the given function.
The first and only input line contains one integer, n, the required number of Fibonacci numbers to return.
Return first n Fibonacci numbers using a generator function.
Create a generator function ‘generatorFunction’, which takes the number of Fibonacci numbers to return (say this is ‘n’). In this function, create a variable ‘count’ initially assigned to one. Create two more variables, ‘a’ and ‘b’, each assigned to 0 and 1, respectively. Now, use a while loop on ‘count’ variable from ‘1’ to’ ‘n’. In each iteration, first, yield ‘a’ and then assign ‘b’ to ‘a’ and ‘a + b’ to ‘b’.
Now, create an empty list, iterate over the ‘generator’ object and insert the items in the list. And Finally, return the list.
// Generator function to generate Fibonacci numbers
function generatorFunction(int n):
function generateFibonacciNumbers(int n):
To calculate the nth Fibonacci number efficiently, we can use memoization. Memoization is a technique of storing previously computed values to avoid redundant calculations.
Algorithm:
Create a function fibMemoization(n, memo) that takes an integer n as input and a vector memo to store the computed Fibonacci values.
Inside the fibMemoization function:
Implement base cases:
If the Fibonacci value for n is already computed (stored in memo[n]), return it.
Otherwise, calculate the Fibonacci value for n using recursion:
Return the computed Fibonacci value for n.
Create a function getFibonacciNumber(n) that takes an integer n as input: